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3 years ago

Select all the equations that have {6} as its solution set.

Mathematics

2 answers:

Lynna [10]3 years ago

7 0

ANSWER:

The ANSWER IS 2. if two solutions are allowed then 2. AND 3. and if your rounding, then 2. 3. and 4.

Step-by-step explanation:

For the first one it is: 0.27... or 3/11

For the second one it is: 6

For the third one it is: 1 or 6, meaning it has two solutions

For the fourth one it is: 6.285714, or 44/7

for the first one: 15-x=54x -> add x to both sides: 15=55x -> then divide both sides by 55: x=3/11

for the second one: 8+3x=6x-10 -> subtract 6x from both sides: 8-3x=-10 -> subtract 8 from both sides: -3x=-18 -> divide both sides by -3: x=6

I'm actually supposed to be doing school, so I don't have time to explain the last two, but I wanted to help, so please give 4 stars or brainliest. and thanks for waiting patiently.

joja [24]3 years ago

5 0

Answer:

8+3x=6x−10

x2+2=7x−4

Step-by-step explanation:

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kenny6666 [7]

Answer:

6) 7.85 7) 32.97

Step-by-step explanation:

6) p= 3.14×(5/2)

p= 7.85

7) p= 3.14×10×5

p= 32.97

4 0

2 years ago

Please help. i don't understand

zaharov [31]

78×.33=25.74 busses are new

25.74+15=40.74 new busses

78+15=93 total busses

40.74/78=0.5223076923= 52% will be new with the new 15 busses

4 0

3 years ago

The measure of an angle is 24°. What is the measure of its supplementary angle?

umka21 [38]

Answer:

156 degree

Step-by-step explanation:

supplementary angle add up to 180 degree

180 - 24

= 156

8 0

2 years ago

Find the domain of the following expression 15 - √(x+2)

ipn [44]

Answer:

[-2, ∞]

Step-by-step explanation:

15 - √(x+2)

domain is any value as long as (x+2) is not-negative, since √ of a negative number has no Real solution.

x+2 ≥ 0 ⇒ x ≥ -2

6 0

3 years ago

5. The superintendent of the local school district claims that the children in her district are brighter, on average, than the g

anygoal [31]

Answer:

We conclude that children in district are brighter, on average, than the general population.

Step-by-step explanation:

We are given the following data set:

105, 109, 115, 112, 124, 115, 103, 110, 125, 99

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1117}{10} = 111.7$

Sum of squares of differences = 642.1

$S.D = \sqrt{\frac{642.1}{49}} = 8.44$

We are given the following in the question:

Population mean, μ = 106

Sample mean, $\bar{x}$ = 111.7

Sample size, n = 10

Alpha, α = 0.05

Sample standard deviation, s = 8.44

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 106\\H_A: \mu > 106$

We use one-tailed(right) t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{111.7 - 106}{\frac{8.44}{\sqrt{10}} } = 2.135$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = 1.833$

Since,

$t_{stat} > t_{critical}$

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

We conclude that children in district are brighter, on average, than the general population.

4 0

3 years ago