since the diameter of the base of the cylinder is 6 feet, then its radius is half that, or 3 feet.
![\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=9 \end{cases}\implies V=\pi (3)^2(9)\implies V=81\pi](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%5C%5C%5C%5C%0AV%3D%5Cpi%20r%5E2%20h~~%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Ar%3D3%5C%5C%0Ah%3D9%0A%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Cpi%20%283%29%5E2%289%29%5Cimplies%20V%3D81%5Cpi)
I did this I think 12 years
The volume of every of the 25 cylindrical containers is 235,500/25 = 9,420 in^3
The formula for the volume of a cylinder is:
V = π(r^2).h
Where π=3.14, r = 2.5 in, V = 9,420 in^3, so you can obtain h as:
h = V / (πr^2) = 9,420 / [(3.14) (2.5^2)] = 480 in
Answer:
The last choice is your answer
Step-by-step explanation:
Plot your point in an x/y coordinate plane. We are in QII where x is negative and y is positive. From that point, if you drop an altitude to the negative x axis, you have a right triangle with a base measure of -2, a height of 5 and a hypotenuse that is unknown as of right now. We will find it using Pythagorean's Theorem. 
The length of the hypotenuse is √29. That means that the cosine of that angle is the side adjacent over the hypotenuse. Rationalizing the denominator gives us 