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Sauron [17]
3 years ago
7

Is this statement correct:

Mathematics
1 answer:
shusha [124]3 years ago
4 0
Fat bussy..... bussy lip fell off at the age of 50...... I think the answer is 72
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Outlier for 35 45 26 32 46 38 39 40 26 72
lesantik [10]

Answer:

72

Step-by-step explanation:

It is the furthest away from the mean.

3 0
3 years ago
Read 2 more answers
A group of 150 middle school students were asked whether they prefer playing video games or watching TV in their spare time.
nalin [4]
A= 44%
B= 42% 


You add 26 and 40 to get 66 and divide by 150. you get .44. Multiply this by 100 and get 44% for A.

You add 40 and 23 to get 63 and divide by 150 again. you get .42. Multiply this by 100 and get 42% for B.





7 0
3 years ago
Exercise 2.2.5. Let [[x]] be the greatest integer less than or equal to x. For example, [[π]] = 3 and [[3]] = 3. For each sequen
Debora [2.8K]

Answer:

a) \lim_{n\rightarrow \infty}a_n=0

b) The limit is [[4/3]]=1, that is, \lim_{n\rightarrow \infty}a_n=1

Step-by-step explanation:

The definition of the limit of a sequence (an) is as follows:

\lim_{n\rightarrow \infty}a_n=L (the sequence (an) converges to L) means that given \epsilon>0, there exists some natural number N such that if n≥N, then |a_n-L|

We will use that [[x]] is a increasing function. That is, if x≤y then [[x]]≤[[y]]

a) For all \epsilon>0, take N≥6. Then 1/N ≤1/6 and 5/N ≤ 5/6 < 1. We have that 0<5/N<1, therefore [[5/N]]=0 (0 is the biggest integer less than or equal than x, for any x on the interval 0<x<1)

For n≥N, we have that 1/n ≤ 1/N, hence 0< 5/n ≤ 5/N < 1 . As we discussed above, [[5/n]]=0. Then |a_n|=0, therefore |a_n-0|=|a_n|=0  

b) For all \epsilon>0, take N≥3/4 (any N will do). Then 1/N ≤ 4/3 and 1/4N ≤ 1/3. Note that a_n=[[(12 + 4n)/3n]]=[[1/4n + 4/3]]

For n≥N, we have that 1/4n ≤ 1/4N, hence 1< 4/3< 1/4n +4/3 ≤ 1/4N+4/3 ≤ 5/3 <2.If 1<x<2 then [[x]]=1 , hence a_n=[[1/4n +4/3]]=1  

Then |a_n-1|=|1-1|=0, therefore |a_n-1|=0

4 0
4 years ago
The lengths of two sides of a right triangle are given. Find the length of the third side. Round to the nearest tenth if necessa
Korvikt [17]
Use Pythagorean Theorem:
28^2+15^2=c^2
1009=c^2
Square both sides:
31.8
A
3 0
3 years ago
Find the circumference and the area of a circle with radius <br> 6yd.
Dima020 [189]
Circumference: 37.7 yards
Area: 113.1 yards^2
4 0
3 years ago
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