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gladu [14]
3 years ago
6

Jan 08, 10:02:49 AM

Mathematics
1 answer:
Anit [1.1K]3 years ago
5 0

Answer:

E AND F

Step-by-step explanation:

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Order the following numbers from least to greatest. √11, -0.4, (-4/3), 0.8, √2
agasfer [191]

Answer:

(-4/3), 0.4, 0.8, √2, √11

Step-by-step explanation:

√11=3.316624790355399849114932736670686683927088545589353597058

0.4

(-4/3) = -1.33333333333333333333333333333333333333333333333333333333

0.8

√2=1.414213562373095048801688724209698078569671875376948073176


Thus :

(-4/3)

0.4

0.8

√2

√11

8 0
4 years ago
Bonita deposited $1300 into a bank account that earned 5.75% simple interest each year. She earned $299 in interest before closi
Stolb23 [73]

Answer: 299*100= 29,900

29,900/5.75= 5,200

answer is 5,200

Step-by-step explanation:

8 0
3 years ago
Show all steps!!!
Lunna [17]
-\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|-\frac{2}{3}-2^3-\frac{2}{3}\left|-\frac{1}{2}\right|^3
\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|=\frac{1}{12}
\frac{2}{3}\left|-\frac{1}{2}\right|^3=\frac{1}{12}
=-\frac{1}{12}-\frac{2}{3}-2^3-\frac{1}{12}
=-\frac{53}{6}
4 0
4 years ago
The number of bacteria can be represented by the equation A(t)=200(.75)^t, wherr A(t) is the amount of bacteria in grams and t i
kupik [55]

Answer:

Step-by-step explanation:

a. This is a decay function, since the final value (A) gets smaller and smaller as the days pass by.

b. The bacteria is decreasing by 75% per day exponentially.

c. In order to calculate the amount of bacteria in a week we simply substitute the variable t for 7 (7 days in a week) and solve for A

A = 200(0.75)^7

A = 26.7 bacteria after 1 week

d. In order to calculate this we need to substitute the variable A with 100 and solve for t

100 = 200(0.75)^t   ... divide both side by 200

0.5 = 0.75^t

\frac{ln(0.5)}{ln(0.75)} = t

2.4 = t

It will be half the initial amount after 2.4 days.

6 0
3 years ago
What's the answer ??????
photoshop1234 [79]
M&0 are similar but not congruent

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3 years ago
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