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2 years ago

I Need Help Please And This Is Due In 1 Hour

Mathematics

1 answer:

alex41 [277]2 years ago

7 0

So the first one is 1 square meter of ceiling, and it says 1 square meter of cieling is 10.75. So the first one is just that, 10.75

The second one says 10 square meters, so just multiply 10.75, by 10.

In which case you get 107.5. So that's the answer.

Third one, it gives you how many ceiling tiles you have. So you divide the 100 tiles by 10.75, which gives you 9.30232558, which becomes 9.3

I'm sure you can figure out the last one.

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How do you know that the right triangles are the bases of the prism

Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

For the right triangular prism, the base is a right triangle with sides of lengths 3 in, 4 in, and 5 in. If the prism has a height of 6 inches

4 0

2 years ago

Use the Pythagorean Theorem to find the measure of the space diagonal line in the box

madreJ [45]

Answer:

14.42inches

Step-by-step explanation:

Given the following

b = 5 in

c = 8in

we are to find the measure of the space diagonal line

Using the pythagoras theoreml

l^2 = b^2 + c^2

l^2 = 13^2 - 5^2

l^2 = 169 -25

l^2 = 144

l = 12in

To get the measure of the space diagonal line in the box, we will use the pythagoras theorem;

s^2 = l^2 + c^2

s^2 = 144 + 8^2

s^2 = 144 + 64

s^2 = 208

s= 14.42inches

Hence the required length ix 14.42inches

3 0

2 years ago

Juan has blood type A, Lilly has blood type AB, and Aaron has blood type O. Is this relation a function? Explain.

nexus9112 [7]

Answer: Yes, this relation is function.

Step-by-step explanation:

A relation is called function if each input has unique output.

It is given that, Juan has blood type A, Lilly has blood type AB, and Aaron has blood type O.

Juan is related to blood type A.

Lilly is related to blood type AB.

Aaron is related to blood type O.

Here, each input has unique output because here each person has unique blood group.

Therefore, this relation is a function.

3 0

2 years ago

Y> - 1/2 x + 3

Anna11 [10]

Answer:

0,3

Step-by-step explanation:

enter in a graphing calculator see where you hits 0

8 0

2 years ago

Read 2 more answers

An airport limousine can accommodate up to four passengers on any one trip. The company will accept a maximum of six reservation

Helga [31]

Answer:

a) 0.3191 = 31.91% probability that at least one individual with a reservation cannot be accommodated on the trip.

b) The expected number of available places when the limousine departs is 0.1.

c) $P(X = 3) = 0.09$

$P(X = 4) = 0.25$

$P(X = 5) = 0.32$

$P(X = 6) = 0.34$

Step-by-step explanation:

For each reservation, there are only two possible outcomes. Either the person appears for the trip, or the person does not. The probability of a person appearing for the trip is independent of any other person. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is given by:

$E(X) = np$

The company will accept a maximum of six reservations for a trip, and a passenger must have a reservation.

This means that $n = 6$

35% of all those making reservations do not appear for the trip.

This means that 100 - 35 = 65% appear, so $p = 0.65$

A) If six reservations are made, what is the probability that at least one individual with a reservation cannot be accommodated on the trip?

This will happen if more than four appear, as the limousine can accommodate up to four passengers on any one trip. So

$P(X > 4) = P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{6,5}.(0.65)^{5}.(0.35)^{1} = 0.2437$

$P(X = 6) = C_{6,6}.(0.65)^{6}.(0.35)^{0} = 0.0754$

$P(X > 4) = P(X = 5) + P(X = 6) = 0.2437 + 0.0754 = 0.3191$

0.3191 = 31.91% probability that at least one individual with a reservation cannot be accommodated on the trip.

B) If six reservations are made, what is the expected number of available places when the limousine departs?

The expected number of arrivals is given by:

$E(X) = np = 6*0.65 = 3.9$

Since the are four places:

4 - 3.9 = 0.1

The expected number of available places when the limousine departs is 0.1.

C) Suppose the probability distribution of the number of reservations made is given in the accompanying table.Number of reservations 3 4 5 6Probability 0.09 0.25 0.32 0.34Let X denote the number of passengers on a randomly selected trip. Obtain the probability mass function of X.

This is the probability of each outcome. So

$P(X = 3) = 0.09$

$P(X = 4) = 0.25$

$P(X = 5) = 0.32$

$P(X = 6) = 0.34$

7 0

2 years ago