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ICE Princess25 [194]
3 years ago
13

What is the slope standard form must be converted to slope intercept form

Mathematics
1 answer:
pychu [463]3 years ago
8 0
The standers slop form is y=mx+b
You might be interested in
Jamie starts a savings account with $75. She deposits $30 in her account a monthly. Her friend Carmen's savings account balance
MrRissso [65]

Answer:

Jamie starts off with 75 in her account and carmen starts with 100, while carmen have originally more since 100 is greater that 75 Jamie adds $30 monthly while carmen add 25 monthly so if we were to do jamies equation b=(30*6)+75 b would equal 255, and for carmen, we would have 250 since b=(25*6)+100 equals 250 meaning that Jamie would have a greater balance after 6 months

7 0
3 years ago
Read 2 more answers
PLEASE HELP CORRECT AND 1ST ANSWER IS BRAINLIEST
poizon [28]

Answer:

<em>m<A = 40 deg</em>

<em>m<B = 60 deg</em>

<em>m<C = 80 deg</em>

Step-by-step explanation:

2x + 3x + 4x = 180

9x = 180

x = 20

m<A = 2x = 2(20) = 40

m<B = 3x = 3(20) = 60

m<C = 4x = 4(20) = 80

m<A = 40 deg

m<B = 60 deg

m<C = 80 deg

6 0
4 years ago
Read 2 more answers
If a translation of T2, –7(x, y) is applied to ΔABC, what are the coordinates of B'?
NikAS [45]

The coordinates of B' are 3 and -12. so option D is correct (3, -12)

<h3>How to find the coordinates of B'?</h3>

The point P(x, y) may undergo translation to form P' by using a defined translation rule :

If given the rule T(a, b) synch that P undergoes translation on T; then we will have P'(x+a; y+b)

Therefore,

The point B has its coordinates as B(1, - 5)

Translation rule, T(2, - 7) then the coordination of B after undergoing transformation according to T2;

B(1, - 5) - - - > T(2, - 7) - - - - > B'(1+2 ; - 5+-7)

= B'(3, -12)

Hence, the coordinates of B' are 3 and -12. so option D is correct.

Learn more about the concept :

brainly.com/question/12463306

#SPJ1

8 0
2 years ago
Find the length of the curve x=e^t e^{-t},\;\;y=5-2t,\;\;0 \le t \le 3.
Oksana_A [137]
\begin{cases}x(t)=e^t+e^{-t}\\y(t)=5-2t\end{cases}\implies\begin{cases}x'(t)=e^t-e^{-t}\\y'(t)=-2\end{cases}

The length of the curve is given by the integral

\displaystyle\int_0^3\sqrt{(e^t-e^{-t})^2+(-2)^2}\,\mathrm dt

Expand and rewrite the integrand:

(e^t-e^{-t})^2+(-2)^2=e^{2t}+2+e^{-2t}
=e^{-2t}(e^{4t}+2e^{2t}+1)
=e^{-2t}(e^{2t}+1)^2
\implies\sqrt{(e^t-e^{-t})^2+(-2)^2}=\dfrac{e^{2t}+1}{e^t}

Now the integral is

\displaystyle\int_0^3\dfrac{e^{2t}+1}{e^t}\,\mathrm dt=\int_0^3(e^t+e^{-t})\,\mathrm dt
=2\displaystyle\int_0^3\cosh t\,\mathrm dt
=2\sinh t\bigg|_{t=0}^{t=3}
=2\sinh 3
7 0
3 years ago
A) If there were 3 elephants at the zoo, how many hippos would there be?
ANEK [815]

Answer:

3 as well lol?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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