Answer:
Answer H.
Step-by-step explanation:
Answer:
The lines intersect at x = 1.5 and y = 1
Step-by-step explanation:
We need to find the intersection of the lines 2x+5y=8 and 6x+y=10.
We need to find the values of x and y by elimination and by substitution.
a) By Elimination:
2x+5y = 8 (1)
6x + y = 10 (2)
Multiply eq(2) with 5 and subtract eq(1) from(2)
30x + 5y = 50
2x + 5y = 8
- - -
___________
28x = 42
x = 1.5
Now putting value of x in eq(2)
6x + y = 10
6(1.5) + y = 10
9 + y = 10
=> y = 10 - 9
y = 1
so, (x,y) = (1.5,1)
The lines intersect at x = 1.5 and y = 1
b) By substitution
2x+5y = 8 (1)
6x + y = 10 (2)
Finding value of y in equation 2 and substituting in eq(1)
y = 10 -6x
2x + 5(10 - 6x) = 8
2x + 50 - 30x = 8
-28x = 8-50
-28x = -42
x = -42/-28
x = 1.5
Now finding value of y by substituting value of x
6x + y = 10
6x = 10-y
x = 10 - y /6
2x + 5y = 8
2(10-y/6) + 5y = 8
10-y/3 + 5y = 8
10 -y +15y/3 = 8
10 +14y = 8*3
+14 y = 24 -10
+14 y = 14
y = 14/14
y = 1
So, (x,y) = (1.5,1)
The lines intersect at x = 1.5 and y = 1
The correct answer is -2/9
I hope this helps.
Have a "AWESOME" day. :)
The range of a log function is generally "all real numbers." The range of F(x) will depend on the domain on which it is defined. If it is defined for all positive numbers x, then the range is (-∞, ∞).
FALSE