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3 years ago

How can I solve proportions for missing sides in geometry?

Mathematics

1 answer:

Nadya [2.5K]3 years ago

3 0

Try either the Law of Sines or the Law if Cosines to use interior angles to create a ratio to the side proportions.

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Is 2/3 equivalent to 5/6

Reptile [31]

No 2/3 is not equivalent to 5/6

please can i have a brainliest

4 0

3 years ago

Read 2 more answers

A company that offers tubing trips down a river rents tubes for a person to use for $20 and “cooler” tubes to carry food and wat

Licemer1 [7]

Answer:

The number of each type of tube does the group rent is 11 tubes for person and 4 “cooler” tubes to carry food and water

Explanation:

The rents for tubes for a person to use = $20

The rents for “cooler” tubes to carry food and water = $12.50.

The rent for a total of 15 tubes = $270

11 tubes whose rent cost $20 = $11 \times 20$

= 220

4 “cooler” tubes rent cost $12.50 = $4 \times 12.5$

= 50

Therefore for 15 tubes = 11 +4= 15

cost = 220 + 50

=270

The number of each type of tube does the group rent is 11 tubes for person and 4 “cooler” tubes to carry food and water

8 0

3 years ago

The factored form of 4 x squared plus 4 x minus 15 is ____________.

Serga [27]

I’m sorry, can you add more detail pls

6 0

2 years ago

Ken grew 4/5 of an inch last year.sang grew 3/8of an inch.who grew more and by how much

beks73 [17]

Ken grew .425 of an inch more than Sang

7 0

3 years ago

Read 2 more answers

Number 1 and 2 please (25 points)

Elenna [48]

Answers:

1) $(3x+2)+(4-5x)=-2x+6$

$(3+2i)+(4-5i)=7-3i$

2) $(1-3x)(2+x)=-3x^{2}-5x+2$

$(1-3i)+(2+i)=5-5i$

Step-by-step explanation:

In mathematics there are rules related to complex numbers, specifically in the case of addition and multiplication:

Addition:

If we have two complex numbers written in their binomial form, the sum of both will be a complex number whose real part is the sum of the real parts and whose imaginary part is the sum of the imaginary parts (similarly as the sum of two binomials).

For example, the addition of these two binomials is:

$(3x+2)+(4-5x)=3x-5x+2+4=-2x+6$

Similarly, the addition of two complex numbers is:

$(3+2i)+(4-5i)=3+4+2i-5i=7-3i$ Here the complex part is the number with the $i$

Multiplication:

If we have two complex numbers written in their binomial form, the multiplication of both will be the same as the multiplication (product) of two binomials, taking into account that $i^{2}=-1$ .

For example, the multiplication of these two binomials is:

$(1-3x)(2+x)=2+x-6x-3x^{2}=-3x^{2}-5x+2$

Similarly, the multiplication of two complex numbers is:

$(1-3i)+(2+i)=2+i-6i-3i^{2}=2-5i-3(-1)=5-5i$

8 0

3 years ago