Answer: An attack where the attackers will interrupt a data transfer happening between parties and in which they will pretend to be the legitimate parties.
Explanation: For example think about two people writing letters to each other back and forth. However you, the attacker can intercept the letters and effectively change the message/contents of the letter going to the other person. This is probably not the best explanation, but simply put a man-in-the-middle attack is when an attacker interupts a transfer and pretends to be the legitimate source.
Answer:
The answer is "
Run the software on the original web browser practically".
Explanation:
The Virtual servers enable you to run programming not programmed to the devices. Let's all presume which Henry's software will operate on computers but not on the mac. Since Mac is unable to run this software, it can practically install Linux on MC and install this.
- The several common software applications such as parallels, VMware, and Virtual machines could be practically used during mac to install windows.
- Its platform operating system from a macOS software perspective is a true physical computer with almost everything set.
the answer is c, occupational safety and health act
Answer:
Explanation:
The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int highest, lowest;
ArrayList<Integer> myArr = new ArrayList<>();
while (true) {
System.out.println("Enter a number [0-10] or -1 to exit");
int num = in.nextInt();
if (num != -1) {
if ((num >= 0) && (num <= 10)) {
count+= 1;
myArr.add(num);
} else {
System.out.println("Wrong Value");
}
} else {
break;
}
}
if (myArr.size() > 3) {
highest = myArr.get(0);
lowest = myArr.get(0);
for (int x: myArr) {
if (x > highest) {
highest = x;
}
if (x < lowest) {
lowest = x;
}
}
System.out.println("Number of Elements: " + count);
System.out.println("Highest: " + highest);
System.out.println("Lowest : " + lowest);
} else {
System.out.println("Number of Elements: " + count);
System.out.println("No Highest or Lowest Elements");
}
}
}