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KATRIN_1 [288]
2 years ago
8

I need help plsmy teacher doesn't help..​

Mathematics
2 answers:
snow_tiger [21]2 years ago
7 0

Answer:

r = 6

Step-by-step explanation:

1 - r = -5

Subtract 1 from both sides

-r = -6

r = 6

Zarrin [17]2 years ago
4 0

Answer: r=6

no problem

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you invest 1000 in an account that pays simple interest of 6% for 30 years what. How much money will you have in 30 years
Genrish500 [490]
A = P(1+rt)
A = 1000(1+.06x30) = 2800
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3 years ago
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5. f(x) = 3x³ - 4x² +6x and g(x)=5x ³+ 2x²- 3x. What is f(x) - g(x)?
sasho [114]

Answer:

<h2>A. -2x³ - 6x² + 9x</h2>

Step-by-step explanation:

f(x)=3x^3-4x^2+6x\\\\g(x)=5x^3+2x^2-3x\\\\f(x)-g(x)=(3x^3-4x^2+6x)-(5x^3+2x^2-3x)\\\\=3x^3-4x^2+6x-5x^3-2x^2-(-3x)\qquad\text{combine like terms}\\\\=(3x^3-5x^3)+(-4x^2-2x^2)+(6x+3x)\\\\=-2x^3-6x^2+9x

8 0
3 years ago
1 2/3 × 2 1/3= in fraction form
REY [17]
The answer is 3 8/9 because you turn it into a mixed number which is 5/3*7/3. Once you multiply you get 35/9. Since it is an improper fraction you turn it into a mixed number by dividing 35/9. In the end, you get 3 8/9 as your final answer. 
6 0
3 years ago
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Three consecutive integers can be represented by the variable n, n+1 and n+2. If the sum of three consecutive integers is 57, wh
pashok25 [27]
You have some unknown integer n, and you know that adding this and the next two integers, n+1 and n+2, gives a total of 57.

This means

n+(n+1)+(n+2)=57

The task is to find all three unknown integers. Notice that if you know the value of n, then you pretty much know the value of the other three integers.

To find n, solve the equation above:

n+(n+1)+(n+2)=3n+3=57\implies 3n=54\implies n=\dfrac{54}3=18

So if 18 is the first integer, then others must be 19 and 20.
7 0
2 years ago
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Max has 5.50. He has eight more quarters than he does nickels. He had four times as many dimes as he has nickels. How many quart
Oliga [24]

Answer:

<h2>There are 13 quarters, 5 nickels and 20 dimes.</h2>

Step-by-step explanation:

Givens

  • Max has $5.50.
  • He has eight more quarters than he does nickels.
  • He had four times as many dimes as he has nickels.

From these statements, we can deduce algebraical expressions to solve the problem. Let's call q quarters, n nickels and d dimes.

q=n+8 (8 more quarters than nickels)

d=4n (he has four times as many dimes as he has nickels).

0.25q+0.05n+0.10d=5.50 (Max has a total of $5.50, one quartes is $0.25, one nickel is $0.05 and one dime is $0.10).

Let's replace the first two expressions into the third equation

0.25(n+8)+0.05n+0.10(4n)=5.50\\0.25n+2+0.05n+0.40n=5.50\\0.70n=5.50-2\\n=\frac{3.50}{0.70}\\ n=5

There are 5 nickels.

Now, we use this value to find the number of quarters

q=5+8=13

There are 13 quarters.

Also, d=4(5)=20

There are 20 dimes.

Therefore, there are 13 quarters, 5 nickels and 20 dimes.

3 0
3 years ago
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