Answer: 
and $475 deposited into the account on her birthdays by her 18th birthday.
Step-by-step explanation:
It is given that, on Gabriela’s first birthday, her parents gave her a $50 savings account.
Initial term : 
On every birthday after that her parents added to the account, increasing the amount they deposited by $25 each year.
Common difference : 
It forms an AP: 50,75,100,...
nth term of an AP is
Substitute and in the above formula.
It represents the amount deposited into the account after n birthdays.
We need to find the amount by her 18th birthday.
Put n=18 in the above equation.
Therefore, $475 deposited into the account on her birthdays by her 18th birthday.
Parameters of functions are the independent variable(s). e.x. y = 2x /\ x is the independent <span> variable (the parameter).</span>
Answer:
1) 5 * 18
Step-by-step explanation:
Because 6*3 = 18
5*6*3 = 5*18
Answer:
a) v = 12.21m/s
a = 4.07 m/s²
b)v = 11.24m/s
a = 3.75 m/s²
Step-by-step explanation:
a) Dividing the moviment into two parts:
I - With acceleration
v = v₀ + at
s = s₀ + v₀t + at²/2
- v₀ = 0
- s₀ = 0
- a = ?
- v = ?
- t = 3s
- s = x
v = v₀ + at
v = 3a ⇒ a = v/3
s = s₀ + v₀t + at²/2
x = v/3.3²/2
x = 3v/2
II - Uniform
s = s₀ + vt
s = 100
s₀ = x
v = v
t = 9.69 - 3 = 6.69s
s = s₀ + vt
100 = x + v*6.69
100 = x + 6.69v
As x = 3v/2
100 = 3v/2 + 6.69v
100 = 1.5v + 6.69v
100 = 8.19v
v = 12.21m/s
a = v/3 = 4.07 m/s²
b) Dividing the moviment into two parts:
I - With acceleration
v = v₀ + at
s = s₀ + v₀t + at²/2
- v₀ = 0
- s₀ = 0
- a = ?
- v = ?
- t = 3s
- s = x
v = v₀ + at
v = 3a ⇒ a = v/3
s = s₀ + v₀t + at²/2
x = v/3.3²/2
x = 3v/2
II - Uniform
s = s₀ + vt
s = 200
s₀ = x
v = v
t = 19.30 - 3 = 16.30s
s = s₀ + vt
200 = x + v*16.3
100 = x + 16.3v
As x = 3v/2
200 = 3v/2 + 16.3v
200 = 1.5v + 16.3v
200 = 17.8v
v = 11.24m/s
a = v/3 = 3.75 m/s²
Answer:
1/3
Step-by-step explanation:
if you move up 1 over three, the line intersects the graph
