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3 years ago

6

Help please due in 10 minutes!!!

1 answer:

polet [3.4K]3 years ago

3 0

Answer:

Step-by-step explanation:

1: You will pay $682.5 for a item with original price of $1050 when discounted 35%. In this example, if you buy an item at $1050 with 35% discount, you will pay 1050 - 367.5 = 682.5 dollars.

2: You will pay $617.5 for a item with original price of $650 when discounted 5%. In this example, if you buy an item at $650 with 5% discount, you will pay 650 - 32.5 = 617.5 dollars.

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The human body is 65% oxygen, 18% carbon! And 10% hydrogen. The rest is other elements. What percent is composed of other elemen

Lubov Fominskaja [6]

Is it 7%? im guesing u add them up

5 0

4 years ago

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Paper plates come in packages of 15 or 20. George bought 10 packages and had a total of 170 plates. How many of each package did

damaskus [11]

The answer to your question is 17

8 0

3 years ago

Misha Larkins [42]

Answer: 24 $in^{2}$

Step-by-step explanation:

A=1/2hb

to find lenth of triangle: the side of the square is 10 and on the top, the triangle takes up 10-6 in so it must be 4 in long

to find height, it is 16-10 in of of the square. so itmust be 6 in

so to find area:

A=1/2*6*4

= 1/2*24

=24

7 0

3 years ago

Trig proofs with Pythagorean Identities.

lorasvet [3.4K]

To prove:

$$\frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}=2 \cot ^{2} x+1$

Solution:

$$LHS = \frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}$

Multiply first term by $\frac{1+cos x}{1+cos x}$ and second term by $\frac{1-cos x}{1-cos x}$ .

$$= \frac{1(1+\cos x)}{(1-\cos x)(1+\cos x)}-\frac{\cos x(1-\cos x)}{(1+\cos x)(1-\cos x)}$

Using the identity: $(a-b)(a+b)=(a^2-b^2)$

$$= \frac{1+\cos x}{(1^2-\cos^2 x)}-\frac{\cos x-\cos^2 x}{(1^2-\cos^2 x)}$

Denominators are same, you can subtract the fractions.

$$= \frac{1+\cos x-\cos x+\cos^2 x}{(1^2-\cos^2 x)}$

Using the identity: $1-\cos ^{2}(x)=\sin ^{2}(x)$

$$= \frac{1+\cos^2 x}{\sin^2x}$

Using the identity: $1=\cos ^{2}(x)+\sin ^{2}(x)$

$$=\frac{\cos ^{2}x+\cos ^{2}x+\sin ^{2}x}{\sin ^{2}x}$

$$=\frac{\sin ^{2}x+2 \cos ^{2}x}{\sin ^{2}x}$ ------------ (1)

$RHS=2 \cot ^{2} x+1$

Using the identity: $\cot (x)=\frac{\cos (x)}{\sin (x)}$

$$=1+2\left(\frac{\cos x}{\sin x}\right)^{2}$

$$=1+2\frac{\cos^{2} x}{\sin^{2} x}$

$$=\frac{\sin^2 x + 2\cos^{2} x}{\sin^2 x}$ ------------ (2)

Equation (1) = Equation (2)

LHS = RHS

$$\frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}=2 \cot ^{2} x+1$

Hence proved.

5 0

4 years ago

Which on the answer please help

Serggg [28]

Answer: D

Step-by-step explanation:

6.5 * 150= 975

4 0

3 years ago