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blondinia [14]
3 years ago
5

What is the image of (5, -7) after a reflection over the x-axis?​

Mathematics
1 answer:
ki77a [65]3 years ago
5 0

Answer:(5,7)

Step-by-step explanation:

I use this graph/graphing calculator or remember this rule

When theres a reflection over the x axis, all the X values say the same and all of the y values are the opposite.

x=5 y=-7 the x aka 5 stays the same and the opposite of -7 is 7

(5,-7) Turns into (5,7)

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Answer:

\displaystyle f'(x) = \frac{4}{x^2}

General Formulas and Concepts:

<u>Calculus</u>

Limits

  • Limit Rule [Variable Direct Substitution]:                                                    \displaystyle \lim_{x \to c} x = c

Differentiation

  • Derivatives
  • Derivative Notation

The definition of a derivative is the slope of the tangent line:                             \displaystyle f'(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

<em />\displaystyle f(x) = -\frac{4}{x}

<u>Step 2: Differentiate</u>

  1. [Function] Substitute in <em>x</em>:                                                                            \displaystyle f(x + h) = -\frac{4}{x + h}
  2. Substitute in functions [Definition of a Derivative]:                                   \displaystyle f'(x) = \lim_{h \to 0} \frac{-\frac{4}{x + h} - \big( -\frac{4}{x} \big)}{h}
  3. Simplify:                                                                                                        \displaystyle f'(x) = \lim_{h \to 0} \frac{4}{x(x+ h)}
  4. Evaluate limit [Limit Rule - Variable Direct Substitution]:                          \displaystyle f'(x) = \frac{4}{x(x+ 0)}
  5. Simplify:                                                                                                        \displaystyle f'(x) = \frac{4}{x^2}

∴ the derivative of the given function will be equal to 4 divided by x².

---

Learn more about derivatives: brainly.com/question/25804880

Learn more about calculus: brainly.com/question/23558817

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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