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3 years ago

Picture below need answer fast

Mathematics

1 answer:

IRINA_888 [86]3 years ago

7 0

Ok can you help me with this 137x8 multiply with expanded form please???? I will help with yours

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A coordinate grid showing Number of Classes on the horizontal x-axis and Total Cost in dollars on the vertical y-axis with 2 lin

Oksana_A [137]

The system of equations representing these costs are; y = 7.5x and y = 5.5x + 10

<h3>How to find the equation of a line?</h3>

The slope of the first line is;

m = (y2 - y1)/(x2 - x1)

m = (32 - 10)/(4 - 0)

m = 5.5

Now, the first coordinate has a y-intercept of 10. Thus, the equation here for the cost is; y = mx + c = 5.5x + 10

The slope of the second line is;

m = (y2 - y1)/(x2 - x1)

m = (15 - 0)/(2 - 0)

m = 7.5

Now, the first coordinate has a y-intercept of 0. Thus, the equation here for the cost is; y = mx + c = 7.5x + 0 = 7.5x

Thus, the system of equations representing these costs are;

y = 7.5x and y = 5.5x + 10

Read more about Equation of a line at; brainly.com/question/13763238

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2 years ago

The head librarian at a public library releases a report. The report states that visitors to the library want the library to ope

IrinaK [193]

1.The sample is biased because it does not represent the population.

2.The question is biased toward a Yes response.

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3 years ago

Find the distance between the two points (-2,-6) and (0,5).

HACTEHA [7]

Answer: OPTION B

Step-by-step explanation:

You can find the distance between two points by using the following formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given the points (-2,-6) and (0,5), you can identify that:

$x_2=-2\\x_1=0\\\\y_2=-6\\y_1=5$

Therefore, substituting values, you get that the distance between those points is:

$d=\sqrt{(-2-0)^2+(-6-5)^2}\\\\d=5\sqrt{5}$

7 0

3 years ago

Read 2 more answers

Use the initial term and the recursive formula to find an explicit formula for the sequence an. Write your answer in simplest fo

agasfer [191]

From the recursive rule

$a_n = a_{n-1}-13$

it follows that

$a_{n-1}=a_{n-2}-13 \implies a_n = a_{n-2} - 2\times13$

$a_{n-2}=a_{n-3}-13 \implies a_n = a_{n-3} - 3\times13$

and so on. Notice how the subscript on a on the right side and the coefficient multiplied by 13 add up to n (n - 2 + 2 = n; n - 3 + 3 = n; and so on). If we continue the pattern, we'll end up with

$a_n = a_1 + (n-1)\times13$

so that the explicit rule for the n-th term in the sequence is

$a_n = -2 + 13(n-1) \implies a_n = \boxed{13n-15}$

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2 years ago

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Irina-Kira [14]

First one is graph C second one is graph B third is graph D

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3 years ago