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Romashka [77]
2 years ago
9

Solve: -2+x=4 Please please answer quickly

Mathematics
1 answer:
sergeinik [125]2 years ago
3 0

Answer:

x = 6

Step-by-step explanation:

-2 + x = 4

x = 4 + 2

x = 6

Thank you :-)

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lighting if a 25-foot-tall house cast a 75-foot shadow at the same time that a streetlight casts a 60-foot shadow how tall is th
jolli1 [7]

Answer:

The street light is 20 feet tall.

Step-by-step explanation:

This question depends on a proportion. Keep your height of the object in one ratio and the length of the shadow in the other.

25/x = 75/60      Notice the height of the structure is on the left. The length of the shadow is on the right. Cross multiply

75x =  60 * 25     Combine the right

75x = 1500          Divide by 75

x = 1500/75

x = 20

The street light is 20 feet tall.

3 0
2 years ago
Use the distributive property then combine any like terms<br><br> 4(7p+4-2p)
ivolga24 [154]

Answer:20p+16

Step-by-step explanation:

Combine like terms

4(7p+4-2p)

4(5p+4)

Distribute

4(5p+4)

20p+16

7 0
3 years ago
Read 2 more answers
350 at 5% interest for 4 years simple interest at the to the nearest cent
Scilla [17]
The answer is $4.40

mutiply 350 by 5% and get 17.5 then divide thag by 4 and you get 4.37 and you supposed to round it up which will be 4.40
3 0
3 years ago
Write 55 as a product of its prime factors
Roman55 [17]

Answer:

55 = 5 × 11

Step-by-step explanation:

The only prime factors of 55 are 5 and 11, thus

55 = 5 × 11

4 0
3 years ago
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In a two-digit number, the tens digit is 5 less than the units digit. The number itself is five more than three times the sum of
Luden [163]

Given:

In a two-digit number, the tens digit is 5 less than the units digit.

The number itself is five more than three times the sum of its digits.

To find:

The number.

Solution:

Let the two digit number is ab. So,

ab=10a+b

Tens digit is 5 less than the units digit.

a=b-5       ...(i)

The number itself is five more than three times the sum of its digits.

10a+b=3(a+b)+5

10a+b=3a+3b+5

10a+b-3a-3b=5

7a-2b=5          ...(ii)

Using (i) and (ii), we get

7(b-5)-2b=5

7b-35-2b=5

5b=5+35

5b=40

b=8

Putting b=8 in (i), we get

a=8-5

a=3

Therefore, the required number is 38.

5 0
3 years ago
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