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3 years ago

How do you round 26.2 to the nearest tenth of a kilometer?

Mathematics

1 answer:

Fittoniya [83]3 years ago

6 0

The answer would be 26 because .1-4 rounds down, 5-9 rounds up

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What is the standard deviation of the following data set rounded to the nearest tenth? 56 ,78 ,123 , 34, 67, 91, 20

quester [9]

Answer:

The standard deviation of the following data set is 32.2

Step-by-step explanation:

step 1

Find the mean

we have

$[56,78,123,34,67,9,20]$

Sum the data and divided by the number of elements

$[56+78+123+34+67+91+20]/7=469/7=67$

step 2

For each number: subtract the Mean and square the result

$[(56-67)^{2},(78-67)^{2},(123-67)^{2},(34-67)^{2},(67-67)^{2},(91-67)^{2},(20-67)^{2}]$

$[121,121,3,136,1,089,0,576,2,209]$

step 3

Work out the mean of those squared differences

$[121+121+3,136+1,089+0+576+2,209]/7=1,036$

This value is called the "Variance"

step 4

Take the square root of the variance

$standard\ deviation=\sqrt{1,036}=32.2$

6 0

3 years ago

What is 118.083 rounded to the nearest tenth and hundredth

charle [14.2K]

Answer: 118.1 and 118.08

Step-by-step explanation:

For tenths 118.1 and for hundredth it is 118.08

6 0

3 years ago

Andy and Elizabeth each rounded 2,639,456 to the nearest ten-thousand. Andy got 2,640,000. Elizabeth got 2,630,000. who is corre

Gelneren [198K]

Andy was correct
2639456 is rounded to 2640000 because the 9 from 39,456 rounds up to 0 and the three changes to a 4
Elizabeth rounded down instead

4 0

3 years ago

Consider the functions below. f(x, y, z) = x i − z j + y k r(t) = 4t i + 6t j − t2 k (a) evaluate the line integral c f · dr, wh

fredd [130]

With

$\vec r(t)=4t\,\vec\imath+6t\,\vec\jmath-t^2\,\vec k$

we have

$\mathrm d\vec r=(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt$

The vector field evaluated over this parameterization is

$\vec f(x,y,z)=\vec f(x(t),y(t),z(t))=4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k$

so the line integral is

$\displaystyle\int_{-1}^1(4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k)\cdot(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt$

$=\displaystyle\int_{-1}^1(16t+6t^2-12t^2)\,\mathrm dt=-4$

6 0

3 years ago

The amount of data left on a cell phone plan is 6 GB

jekas [21]

Answer: ok?

Step-by-step explanation:

8 0

3 years ago