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sergij07 [2.7K]
3 years ago
15

How do you round 26.2 to the nearest tenth of a kilometer?

Mathematics
1 answer:
Fittoniya [83]3 years ago
6 0
The answer would be 26 because .1-4 rounds down, 5-9 rounds up
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Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,
vichka [17]

Answer:

A(-1,0) is a local maximum point.

B(-1,0)  is a saddle point

C(3,0)  is a saddle point

D(3,2) is a local minimum point.

Step-by-step explanation:

The given function is  

f(x,y)=x^3+y^3-3x^2-3y^2-9x

The first partial derivative with respect to x is  

f_x=3x^2-6x-9

The first partial derivative with respect to y is  

f_y=3y^2-6y

We now set each equation to zero to obtain the system of equations;

3x^2-6x-9=0

3y^2-6y=0

Solving the two equations simultaneously, gives;

x=-1,x=3  and y=0,y=2

The critical points are

A(-1,0), B(-1,2),C(3,0),and D(3,2).

Now, we need to calculate the discriminant,

D=f_{xx}(x,y)f_{yy}(x,y)-(f_{xy}(x,y))^2

But, we would have to calculate the second partial derivatives first.

f_{xx}=6x-6

f_{yy}=6y-6

f_{xy}=0

\Rightarrow D=(6x-6)(6y-6)-0^2

\Rightarrow D=(6x-6)(6y-6)

At A(-1,0),

D=(6(-1)-6)(6(0)-6)=72\:>\:0 and f_{xx}=6(-1)-6=-18\:

Hence A(-1,0) is a local maximum point.

See graph

At B(-1,2);

D=(6(-1)-6)(6(2)-6)=-72\:

Hence, B(-1,0) is neither a local maximum or a local minimum point.

This is a saddle point.

At C(3,0)

D=(6(3)-6)(6(0)-6)=-72\:

Hence, C(3,0) is neither a local minimum or maximum point. It is a saddle point.

At D(3,2),

D=(6(3)-6)(6(2)-6)=72\:>\:0 and f_{xx}=6(3)-6=12\:>\:0

Hence D(3,2) is a local minimum point.

See graph in attachment.

3 0
3 years ago
I can not figure out how to do this question and I need help please
spayn [35]
\bf \textit{quadratic formula}\\\\

\begin{array}{lcclll}
1x^2&-6x&+12&=0\\
\uparrow &\uparrow &\uparrow \\
a&b&c
\end{array}
\qquad \qquad 
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}
6 0
3 years ago
Satin ribbon is sold for
Nutka1998 [239]

Answer:

1892.3

Step-by-step explanation:

221 ounces in pounds is 13.8125 pounds to you multiply that by 137 to get your total of 1892.3125

3 0
2 years ago
Why is 2020 edge so hard and annoying I’m on edge 10 hours a day! Here is 14 points
lakkis [162]

Answer:

hey i lucked out again

Step-by-step explanation:

And yea 2020 edge is very hard

5 0
2 years ago
Read 2 more answers
en un colegio mixto hay x estudiantes distribuidos en c cursos. Si hay m niños por curso, ¿Cuantas niñas hay en el colegio?
Tomtit [17]

La ecuación que nos dice cuantas niñas hay en el colegio es:

A = x - c*m

¿Como encontrar una expresión para la cantidad de niñas?

Sabemos que hay un total de x estudiantes, definimos las variables:

  • A = cantidad total de niñas
  • B = cantidad total de niños.

Entonces tenemos A + B = x

Tambien sabemos que los estudiantes estan divididos en c cursos, de tal forma que hay m niños por curso.

Entonces c por m es igual a la cantidad total de niños:

c*m = B

Reemplazando esto en la ecuación de arriba podemos obtener:

A + c*m = x

A = x - c*m

Esta es la ecuación que nos da el numero total de niñas en el colegio.

Sí quieres aprender más sobre ecuaciones, puedes leer:

brainly.com/question/18168483

4 0
2 years ago
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