<span>Yes, that would be called an ionic~ bond.</span>
Q1)
the reaction that takes place is
lead nitrate reacting with potassium iodide to form lead iodide and potassium nitrate
balanced chemical equation for the reaction is as follows
Pb(NO₃)₂ + 2KI ----> PbI₂ + 2KNO₃
Q2)
mass of lead nitrate present - 0.600 g
number of moles = mass present / molar mass
number of moles - 0.600 g / 331.2 g/mol = 0.00181 mol
Q3)
mass of potassium iodide present - 0.850 g
number of moles = mass present / molar mass
number of moles of potassium iodide = 0.850 g / 166 g/mol = 0.00512 mol
Q4)
we have to calculate the number of moles of PbI₂ formed based on the number of moles of Pb(NO₃)₂ present assuming the whole amount of Pb(NO₃)₂ was used up
stoichiometry of Pb(NO₃)₂ to PbI₂ is 1:1
number of Pb(NO₃)₂ moles reacted - 0.00181 mol
therefore number of PbI₂ moles formed - 0.00181 mol
Q5)
next we have to calculate the number of moles of PbI₂ formed based on the amount of KI moles present , assuming all the moles of KI were used up in the reaction
stoichiometry of KI to PbI₂ is 2:1
number of moles of KI reacted - 0.00512 mol
then number of moles of PbI₂ formed - 0.00512 x 2 = 0.0102 mol
0.0102 mol of PbI₂ is formed
Q6)
limting reactant is the reactant that is fully consumed during the reaction. the amount of product formed depends on the amount of limiting reactant present
if lead nitrate is the limiting reactant
if 1 mol of Pb(NO₃)₂ reacts with 2 mol of KI
then 0.00181 mol of Pb(NO₃)₂ reacts with - 2 x 0.00181 mol of KI = 0.00362 mol
but 0.00512 mol of KI is present and only 0.00362 mol are required
therefore KI is in excess and Pb(NO₃)₂ is the limiting reactant
Pb(NO₃)₂ is the limiting reactant
Q7)
then the amount of PbI₂ formed depends on amount of Pb(NO₃)₂ present
therefore number of moles of PbI₂ formed is based on number of Pb(NO₃)₂ moles present
as calculated in Question number 4 - Q4
number of PbI₂ moles formed - 0.00181 mol
mass of PbI₂ formed - 461 g/mol x 0.00181 mol = 0.834 g
mass of PbI₂ formed - 0.834 g
Q8)
actual yield obtained is not always equal to the theoretical yield . therefore we have to find the percent yield. This tells us the percentage of the theoretical yield that is actually obtained after the experiment
percent yield = actual yield / theoretical yield x 100 %
percent yield = 0.475 g / 0.834 g x 100 % = 57.0 %
percent yield of lead iodide is 57.0 %
Quantum states of electrons are usually written in terms of four numbers: the principle quantum number (n), the angular momentum azimuthal number (L), the magnetic quantum number (ml), and the spin projection number (ms). The quantum number set (4,1,0,+1/2) and (4,1,1,+1/2) share the same principle quantum numbers and therefore both sit in the n=4 electron shell.
1.08 atm is the pressure for a certain tire in atmosphere.
<u>Explanation:</u>
One kilo pascal (1 kPa) corresponds to 1000 pascal. Another common unit used for pressure is atmosphere (symbolised as ‘atm’). 1 atm refers the standard atmospheric pressures and corresponds to 760 mm Hg and 101.3 kPa. Atmospheric pressures are commonly referred as square inches (psi)/ pounds.
![1 \mathrm{atm}=101.3 \mathrm{kPa}=101,325 \mathrm{Pa}=760 \mathrm{mm} \mathrm{Hg}=760 \text { torr }=14.7 \mathrm{lb} / \mathrm{in}^{2}(\mathrm{psi})](https://tex.z-dn.net/?f=1%20%5Cmathrm%7Batm%7D%3D101.3%20%5Cmathrm%7BkPa%7D%3D101%2C325%20%5Cmathrm%7BPa%7D%3D760%20%5Cmathrm%7Bmm%7D%20%5Cmathrm%7BHg%7D%3D760%20%5Ctext%20%7B%20torr%20%7D%3D14.7%20%5Cmathrm%7Blb%7D%20%2F%20%5Cmathrm%7Bin%7D%5E%7B2%7D%28%5Cmathrm%7Bpsi%7D%29)
Given:
The air pressure for a certain tire = 109 kPa
We need to find pressure in atmospheres
So, we know,
1 atm = 101.3 kPa
Hence,
![\frac{109 \mathrm{kPa}}{1} \times \frac{1 \mathrm{atm}}{101.3 \mathrm{kPa}}=1.076=1.08 \mathrm{atm}](https://tex.z-dn.net/?f=%5Cfrac%7B109%20%5Cmathrm%7BkPa%7D%7D%7B1%7D%20%5Ctimes%20%5Cfrac%7B1%20%5Cmathrm%7Batm%7D%7D%7B101.3%20%5Cmathrm%7BkPa%7D%7D%3D1.076%3D1.08%20%5Cmathrm%7Batm%7D)
1.08 atm is the pressure for a certain tire in atmosphere.
From the information provided in the question, we can see that; the electron moved up to an energy level and has an energy of 21.72 x 10-19 J.
Bohr's model of the atom tells us that electrons are found in certain specific energy levels. Energy is absorbed when an electron moves from a lower to a higher energy level and energy is released when an electron moves from a higher to a lower energy level.
Given that;
ΔE = E2 - E1
E2 = final energy level
E1 = initial energy level
E2 = ?
E1 = 16.32 x 10-19 J
ΔE = 5.4 x 10-19
E2 = ΔE + E1
E2 = 5.4 x 10-19 + 16.32 x 10-19 J
E2 = 21.72 x 10-19 J
Learn more: brainly.com/question/4612545