Answer:
B. CO₂ and H₂O.
Explanation:
When any organic substance undergoes complete combustion, it produces carbon dioxide (CO₂) and water (H₂O).
In the case of methane, the balanced reaction is:
With the above information in mind the correct answer is option B. CO₂ and H₂O.
When the combustion is incomplete, carbon monoxide (CO) is produced as well.
Answer:
The answer is 465.6 mg of MgI₂ to be added.
Explanation:
We find the mole of ion I⁻ in the final solution
C = n/V -> n = C x V = 0.2577 (L) x 0.1 (mol/L) = 0.02577 mol
But in the initial solution, there was 0.087 M KI, which can be converted into mole same as above calculation, equal to 0.02242 mol.
So we need to add an addition amount of 0.02577 - 0.02242 = 0.00335 mol of I⁻. But each molecule of MgI₂ yields two ions of I⁻, so we need to divide 0.00335 by 2 to find the mole of MgI₂, which then is 0.001675 mol.
Hence, the weight of MgI₂ must be added is
Weight of MgI₂ = 0.001675 mol x 278 g/mol = 0.4656 g = 465.6 mg
Answer:
One mole of water was produced from this reaction.
Explanation:
According to this question, the following equation is given as follows:
2H2 + O2 → 2H2O
Two (2) moles of hydrogen gas produces two (2) moles of water in this balanced chemical equation.
If 1 mole of hydrogen gas was used, then:
1 × 2/2 moles of water would be produced
1 mole of water would be produced.
Denitrification is part of the nitrogen cycle
Heptane means seven carbon atoms and since the general formula is CnH2n+2, heptane will be C7H16
