If he drains 1/8 of a gallon in 1/2, the amount he will drain in one hour is twice as much as 1/8.
Mateo will drain 2/8 (simplified: 1/4) of a gallon in one hour.
Answer:
13 ft/s
Step-by-step explanation:
t seconds after the boy passes under the balloon the distance between them is ...
d = √((15t)² +(45+5t)²) = √(250t² +450t +2025)
The rate of change of d with respect to t is ...
dd/dt = (500t +450)/(2√(250t² +450t +2025)) = (50t +45)/√(10t² +18t +81)
At t=3, this derivative evaluates to ...
dd/dt = (50·3 +45)/√(90+54+81) = 195/15 = 13
The distance between the boy and the balloon is increasing at the rate of 13 ft per second.
_____
The boy is moving horizontally at 15 ft/s, so his position relative to the spot under the balloon is 15t feet after t seconds.
The balloon starts at 45 feet above the boy and is moving upward at 5 ft/s, so its vertical distance from the spot under the balloon is 45+5t feet after t seconds.
The straight-line distance between the boy and the balloon is found as the hypotenuse of a right triangle with legs 15t and (45+5t). Using the Pythagorean theorem, that distance is ...
d = √((15t)² + (45+5t)²)
Step-by-step explanation:
4x + 7x + 2° = 90° { being complementary angles }
11x = 90° - 2°
11x = 88°
x = 88° / 11
x = 8°
<YVZ = <em>7</em><em> </em><em>*</em><em> </em><em>8</em><em>°</em><em> </em><em>+</em><em> </em><em>2</em><em>°</em><em> </em><em>=</em><em> </em><em>5</em><em>8</em><em>°</em>
<em>Hope </em><em>it </em><em>will </em><em>help </em><em>:</em><em>)</em>
The third option is correct
Answer:
<h2>D. √136</h2><h2 />
Step-by-step explanation:
see attached sketch