Maximum height is at dH/dt=0
H= -16T^2+80T+5
dH/dt=-32T+80
-32T+80=0
32T=80
T=2.5s when height is max
Hmax=-16(2.5)^2+80*2.5)+5
=105ft
catching the ball at 5' means solve for T at H=5
H= -16T^2+80T+5=5
-16T^2+80T=0
-16T(T-5)=0
so T=0 cannot be the ans or T=5s
Answer:
4/4 = 1
Step-by-step explanation:
Answer:
5n units
Step-by-step explanation:
C=2πr =2·π·2.5
Answer:
-25
Step-by-step explanation:
The anwser is a hope it helps
