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2 years ago

What is the LCM of 72,96,120

Mathematics

2 answers:

marissa [1.9K]2 years ago

6 0

Answer:

LCM = 1440

Step-by-step explanation:

2 | 72 , 96 , 120

2 | 36, 48, 60

2 | 18 , 24 , 30

2 | 9 , 12 , 15

2 | 9 , 6 , 15

3 | 9 , 3 , 15

3 | 3 , 1 , 5

5 | 1 , 1 , 5

| 1 , 1 , 1

LCM = 2 x 2 x 2 x 2 x 2 x 3 x 3 x 5 = 1440

Tatiana [17]2 years ago

3 0

1440 is the answer to that I believe.

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3 years ago

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A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula

Ilia_Sergeevich [38]

Answer: A. $A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}$

B. A'(5) = 1.76 cm/s

Step-by-step explanation: Rate of change measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

$A=\pi.r^{2}$

So to find the rate of the area:

$\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}$

$\frac{dA}{dr} =2.\pi.r$

Using $r(t)=3-\frac{363}{(t+11)^{2}}$

$\frac{dr}{dt}=\frac{726}{(t+11)^{3}}$

Then

$\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]$

$\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}$

Multipying and simplifying:

$\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$

The rate at which the area is increasing is given by expression $A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$ .

B. At t = 5, rate is:

$A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}$

$A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}$

$A'(5)=\frac{2408693760\pi}{4294967296}$

$A'(5)=1.76268$

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

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2 years ago

M= i + r ; solve for r

Alex777 [14]

Answer:

m - i = r

Step-by-step explanation:

In this question, you are solving for "r".

Solve:

M= i + r

We have to get "r" by itself, so subtract "i" from both sides.

m - i = r

Since we found what "r" is, we can't solve any further.

m - i = r would be your answer.

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2 years ago