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iris [78.8K]
2 years ago
12

What is the counterexample for the city of Portland is in Oregon

Mathematics
2 answers:
Karolina [17]2 years ago
6 0
A counterexample<span> is a special kind of </span>example<span> that disproves a statement or proposition. </span>

The counter example for : the city of Portland is in Oregon would be : the city of Portland is in Maine.

The city named Portland can be found in both states.
In-s [12.5K]2 years ago
4 0

One <em><u>possible counterexample</u></em> would be:

The city of Portland is in Connecticut.

Explanation:

A counterexample is something that proves a statement wrong.  Since the city of Portland is in multiple states (Oregon, Maine, Connecticut, Arkansas, etc.), any of the other states having a Portland would serve as a counterexample.

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Andre owned a 1/4 acre lot. He wanted to construct a 120’ x 80’ tennis court on the lot. How many square feet will remain uncove
OLga [1]

The area of the tennis court is computed by multiplying the dimensions given,

                               A = 120' x 80'

                               A = 9600 ift


Then, we convert the area in ft² to acres,

                       A = (9600 in²)(2.3 x 10^-5/ 1 in²)

                           A = 0.24 acre


The portion of land remaining is,

                  A of remaining = 0.25 acre - 0.24 acre

                                           = 0.1 acre


The remaining portion is for Andre's studies.


This, 0.1 ft² is equal to the 4% of the given area of the court. 

3 0
3 years ago
Helppppp plzzzz ASAP!!!!!!<br> Thank you!!!!!!
Zielflug [23.3K]

Answer:

option 4.

16 square units

Step-by-step explanation:

as we do not have the measures of the sides, but if the points of the vertices with Pythagoras we can calculate the sides.

P = (2 , 4)

S = (4 , 2)

we have to subtract the values ​​of p from s

PS = (4 - 2  , 2 - 4)

PS = (2 , -2)

by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2

h: hypotenuse

c1: leg 1

c2: leg 2

PS^2 = 2^2 + -2^2

PS = √ 4 + 4

PS = √8

PS = 2√2

S = (4 , 2)

R = (8 , 6)

SR = (8-4  ,  6-2)

SR = (4 , 4)

by pitagoras h ^ 2 = c1 ^ 2 + c2 ^ 2

h: hypotenuse

c1: leg 1

c2: leg 2

SR^2 = 4^2 + 4^2

SR = √ (16 + 16)

SR = √32

SR = 4√2

having the values ​​of 2 of its sides we multiply them and obtain their area

PS * RS = Area

2√2 * 4√2 =

16

3 0
3 years ago
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