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3 years ago

How to turn a mixer number to a improper fraction

2 answers:

5 0

For example, a mix number like 1 ½ basically equals to a whole and a half and in this case the whole would be 2 and the half of 2 is 1. hence, the improper fraction of 1 ½ is 3/2.

Bond [772]3 years ago

4 0

Step-by-step explanation:

1. keep the demoninator the same

2. to find the numberator, multiply the demoninator number by the whole number, and add the product of that with the numerator number.

example:

2 3/8 = 19/8

1. so, keep the denominator the same, which means that the denominator is 8

2. to find the numerator, you do:

8 times 2 = 16

16 + 3 = 19

therefore, the improper fraction of 2 3/8 is 19/8

i hope that helps explain/clarify what you're confused with. :D

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Elodia [21]

Given:

The table of values for the function f(x).

To find:

The values $f^{-1}(f(3.14))$ and $f(f(-7))$ .

Solution:

From the given table, it is clear that the function f(x) is defined as:

$f(x)=\{(-14,11),(-7,-12),(-12,-5),(9,1),(10,-2),(-2,13)\}$

We know that if (a,b) is in the function f(x), then (b,a) must be in the function $f^{-1}(x)$ . So, the inverse function is defined as:

$f^{-1}(x)=\{(11,-14),(-12,-7),(-5,-12),(1,9),(-2,10),(13,-2)\}$

And,

$f^{-1}(f(a))=f^{1}(b)$

$f^{-1}(f(a))=a$ ...(i)

Using (i), we get

$f^{-1}(f(3.14))=3.14$

Now,

$f(f(-7))=f(-12)$

$f(f(-7))=5$

Therefore, the required values are $f^{-1}(f(3.14))=3.14$ and $f(f(-7))=5$ .

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x = -8

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