Answer:
Perimeter of the summer camp = 38 units
Step-by-step explanation:
Distance between P(5, 14) and Q(8, 14) = 8 - 5
= 3 units
Distance between Q(8, 14) and R(8, 2) = 14 - 2
= 12 units
Distance between R(8, 2) and S(1, 2) = 8 - 1
= 7 units
Distance between S(1, 2) and T(1, 8) = 8 - 2
= 6 units
Distance between T(1, 8) and U(5, 8) = 5- 1
= 4 units
Distance between U(5, 8) and P(5, 14) = 14 - 8
= 6 units
Therefore, perimeter of the summer camp = 3 + 12 + 7 + 6 + 4 + 6
= 38 units
Answer:
Step-by-step explanation:
Given that at time t, the position of a body moving along the s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m
i.e.
Velocity is nothing but s'(t) = derivative of s
and acceleration is s"(t) = derivative of v(t)
a) v(t) =0 when t = 4 or 6
b)
a(t) =0 when t =5
c) Distance travelled by the body from 0 to 5 would be
i.e. 110 miles (distance cannot be negative)
Step-by-step explanation:
everything can be found in the picture
