3/7 to its decimal form and rounded to the nearest thousandth

How do you write this polynomial in standard form?

Butoxors [25]

Answer:

You can also work on the ways that you write polynomials. One way to write a polynomial is in standard form. In order to write any polynomial in standard form, you look at the degree of each term. You then write each term in order of degree, from highest to lowest, left to right.

Step-by-step explanation:

Write the expression 3x−8+4x5 in standard form.

First, look at the degrees for each term in the expression.

3x has a degree of 1

8 has a degree of 0

4x5 has a degree of 5

Next, write this trinomial in order by degree, highest to lowest

4x5+3x−8

The answer is 4x5+3x−8.

The degree of a polynomial is the same as the degree of the highest term, so this expression is called a fifth degree trinomial.

4 0

3 years ago

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A study in your town found that 54 in 1,762 people have a post office box what percent of the people in town have a post office

gavmur [86]

Multiply 54 times 100 then divide by 1,762

54 times 100= 5400

5400\1,762= .03

which equals to 3%

4 0

3 years ago

(x +y)^5<br> Complete the polynomial operation

Vesna [10]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the polynomial

$\left(x+y\right)^5$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=x,\:\:b=y$

$=\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i$

so expanding summation

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$

solving

$\frac{5!}{0!\left(5-0\right)!}x^5y^0$

$=1\cdot \frac{5!}{0!\left(5-0\right)!}x^5$

$=1\cdot \:1\cdot \:x^5$

$=x^5$

also solving

$=\frac{5!}{1!\left(5-1\right)!}x^4y$

$=\frac{5}{1!}x^4y$

$=\frac{5x^4y}{1}$

$=5x^4y$

similarly, the result of the remaining terms can be solved such as

$\frac{5!}{2!\left(5-2\right)!}x^3y^2=10x^3y^2$

$\frac{5!}{3!\left(5-3\right)!}x^2y^3=10x^2y^3$

$\frac{5!}{4!\left(5-4\right)!}x^1y^4=5xy^4$

$\frac{5!}{5!\left(5-5\right)!}x^0y^5=y^5$

so substituting all the solved results in the expression

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$

$=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

Therefore,

$\left(x\:+y\right)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

6 0

2 years ago

The triangles are similar. What is the value of x? Enter your answer in the box. x = two right triangles. the larger triangle ha

Mama L [17]

<span>Since the triangles are right triangles, the hypotenuse can be calculated using the Pythagorean theorem:
5²+12²=x²
x²=25+144, x²=169⇒x=√169
x=13
The hypotenuse of a smaller triangle is 13 units.</span>

8 0

3 years ago

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Triangle ABC is shown with four images that are each the result of a transformation of triangle ABC. On a coordinate plane, tria

docker41 [41]

Answer:ghi

Step-by-step explanation:

8 0

2 years ago

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