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3 years ago

13

honestly i'm ready to give up, I need help but nobody's helping and it's extremely stressful so could someone please help. and n

ot send a virus or po-rn- pic?

1 answer:

Keith_Richards [23]3 years ago

7 0

Answer:

b-d-e

Step-by-step explanation:

I think i could completly wrong

* someone sent u p-orn?*

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Answer:

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Step-by-step explanation:

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A rectangle width is one fourth it’s length, outs are is 9 square units. The equation I(1/4I)=9 can be used to find I, the lengt

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Answer:

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Step-by-step explanation:

Let

L -----> the length of rectangle

W ----> the width of rectangle

we know that

The area of rectangle is equal to

$A=LW$

we have

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$9=LW$ -----> equation A

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so

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$9=L(\frac{1}{4}L)$

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$L^{2}=36$

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3 years ago

Write an equation in standard form of the hyperbola described.

marishachu [46]

Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.

$\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill$

$\begin{cases} h=0\\ k=0\\ a=2\\ c=4 \end{cases}\implies \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{b^2} \\\\\\ c^2=a^2+b^2\implies 4^2=2^2+b^2\implies 16=4+b^2\implies \underline{12=b^2} \\\\\\ \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{12}\implies \boxed{\cfrac{x^2}{4}-\cfrac{y^2}{12}}$

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2 years ago

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3 years ago

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s344n2d4d5 [400]

Answer:

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Step-by-step explanation:

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