Answer:
a = 2, b = -9, c = 3
Step-by-step explanation:
Replacing x, y values of the points in the equation y = a*x^2 + b*x +c give the following:
(-1,14)
14 = a*(-1)^2 + b*(-1) + c
(2,-7)
-7 = a*2^2 + b*2 + c
(5, 8)
8 = a*5^2 + b*5 + c
Rearranging:
a - b + c = 14
4*a + 2*b + c = -7
25*a + 5*b + c = 8
This is a linear system of equations with 3 equations and 3 unknows. In matrix notation the system is A*x = b whith:
A =
1 -1 1
4 2 1
25 5 1
x =
a
b
c
b =
14
-7
8
Solving A*x = b gives x = Inv(A)*b, where Inv(A) is the inverse matrix of A. From calculation software (I used Excel) you get:
inv(A) =
0.055555556 -0.111111111 0.055555556
-0.388888889 0.444444444 -0.055555556
0.555555556 0.555555556 -0.111111111
inv(A)*b
2
-9
3
So, a = 2, b = -9, c = 3
Answer:its b
first off its a straight line ill give it that but its not going through the origin is think its b
hoped this helped lmk if it did
Answer:
f(-2) = -1
Step-by-step explanation:
One way of doing this is to substitute -2 for x in every place where x shows up:
f(x) = 4x + 3x^2 − 5 → f(-2) = 4(-2) + 3(-2)^2 − 5
→ f(-2) = -8 + 3(4) - 5, or f(-2) = 4 - 5, or f(-2) = -1
Answer:
Part of mathematics in which letters and other symbols are used to represent numbers and quantities in formula and equation Algebra is one of the broad parts of mathematics, together with number theory, geometry and analysis
Step-by-step explanation:
