I need help plszszszsz

-2(z+3)-z=-z-4(z+2)<br> solve for z quickly please! will give brainliest

anyanavicka [17]

Answer:

$\sf z = - \dfrac{2}{3}$

Step-by-step explanation:

Solve for z:

$\longrightarrow$ -2(z + 3) = -z - 4(z + 2)

-4(z + 2) = -4z - 8:

$\longrightarrow$ -2(z + 3) = -z -4z - 8

Grouping like terms, -z - 4z - 8 = (-z - 4z) - 8:

$\longrightarrow$ -2(z + 3) = (-z - 4z) - 8

-z - 4z = -5z:

$\longrightarrow$ -2 (z + 3) = -5z - 8

Expand out terms of the left hand side:

$\longrightarrow$ -2z - 6 = -5 z - 8

Add 5z to both sides:

$\longrightarrow$ (5z - 2z) - 6 = (5z - 5z) - 8

5z - 5z = 0:

$\longrightarrow$ (5z - 2z) - 6 = -8

5z - 2z = 3z:

$\longrightarrow$ 3z - 6 = -8

Add 6 to both sides:

$\longrightarrow$ 3z + (6 - 6) = 6 - 8

6 - 6 = 0:

$\longrightarrow$ 3z = 6 - 8

6 - 8 = -2:

$\longrightarrow$ 3z = -2

Divide both sides of 3z = -2 by 3:

$\longrightarrow$ $\sf \dfrac{3}{3}z = - \dfrac{2}{3}$

$\sf \dfrac{3}{3} = 1 :$

$\longrightarrow$ $\sf z = - \dfrac{2}{3}$

7 0

3 years ago

Read 2 more answers

Help Me! I suck with vectors.<br> Look at the attached pictures for the problem.

Westkost [7]

Multiplying a vector $x$ by a constant $k$ gives you a new vector whose components are the same as $x$ , but scaled by $k$ :

$x=\langle x_1,x_2\rangle\implies x=\langle kx_1,kx_2\rangle$

So we have

$u=\langle5,-7\rangle\implies-6u=\langle-30,42\rangle$

$v=\langle-11,3\rangle\implies2v=\langle-22,6\rangle$

Vector addition is just a matter of adding the corresponding components together:

$x=\langle x_1,x_2\rangle,y=\langle y_1,y_2\rangle\implies x+y=\langle x_1+y_1,x_2+y_2\rangle$

Then

$2v-6u=\langle-22,6\rangle+\langle-30,42\rangle=\langle-22-30,6+42\rangle$

$\implies\boxed{2v-6u=\langle-52,48\rangle}$

$\|x\|$ denotes the norm/magnitude of the vector $x$ :

$x=\langle x_1,x_2\rangle\implies\|x\|=\sqrt{{x_1}^2+{x_2}^2}$

We have

$\|2v-6u\|=\sqrt{(-52)^2+48^2}=4\sqrt{313}$

$\implies\boxed{\|2v-6u\|\approx70.77}$

7 0

4 years ago

The circumference of a circular region is shown. What type of number best describes the diameter of the

lakkis [162]

Yes is would the diameter of -1 mile east of the integer

6 0

4 years ago

Before a check can be deposited or cashed it must be

liraira [26]

Before a check can be deposited or cashed it must be signed.

5 0

4 years ago

Prove that when a polynomial function p(x) is divided by a first degree polynomial ax + b the remainder is p(-b/a)

DochEvi [55]

Answer:

r = p(-b/a)

Step-by-step explanation:

Let p(x) = q(x)(ax + b) + r(x) where q(x) is the quotient when p(x) is divided by ax + b and r(x) is the remainder.

Since ax + b is a first degree polynomial, r(x) is one power less than ax + b is is just a constant, r.

So, p(x) = q(x)(ax + b) + r

Now, p(x) = r when q(x)(ax + b) = 0

since q(x) ≠ 0, ax + b = 0 ⇒ ax = -b ⇒ x = -b/a

⇒ p(x) = r when x = -b/a

So, r = p(-b/a)

So, the remainder when a polynomial function p(x) is divided by a first degree polynomial ax + b is p(-b/a)

8 0

3 years ago