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3 years ago

Find the area of a triangle with vertices (-2,2), (1,5) and (6,-1).

Mathematics

1 answer:

Mamont248 [21]3 years ago

6 0

The solution in the attachment (two methods)

Answer: D. 16.5 u²

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Morgan's juice glass holds 225 millimeters.If she uses the glass to drink 8 glasses of water everyday how many liters does she d

NeTakaya

225*8=1,800
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4 years ago

The polynomial of degree 3 , P ( x ) , has a root of multiplicity 2 at x = 1 and a root of multiplicity 1 at x = − 2 . The y -in

Citrus2011 [14]

Answer:

The polynomial of degree 3 ,P(x), has a root of multiplicity 2 at x=1 and a root of multiplicity 1 at x=−1. The y-intercept is y=−0.2

3 0

3 years ago

Can someone else help me out

icang [17]

your answer is B 2 million

3 0

3 years ago

Determine number of solutions

kenny6666 [7]

No solution
Cause if you substitute the y
Ur final answer will be -2
When we have negative in the answer
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6 0

3 years ago

For points K (-6,6) and P (-3,-2), find the following:m:| m:I m:Distance:Equation of a line 1:

atroni [7]

From the question

We are given the points

$K(-6,6),P(-3,-2)$

Finding the slopre, m

Slope is calculated using

$m=\frac{y_{2_{}}-y_1}{x_2-x_1}$

From the given points

$\begin{gathered} x_1=-6,y_1=6 \\ x_2=-3,y_2=-2 \end{gathered}$

Therefore,

$\begin{gathered} m=\frac{-2-6}{-3-(-6)} \\ m=\frac{-8}{-3+6} \\ m=\frac{-8}{3} \end{gathered}$

Therefore, m = -8/3

The next thing is to find

$\mleft\Vert m\mright?$

A slope parallel to m

For parallel lines, slopes are equal

Therefore,

$\mleft\Vert m=-\frac{8}{3}\mright?$

Next, we are to find

$\perp m$

A slope perpendicular to m

For perpendicular lines, the product of the slopes = -1

Therefore

$\perp m=-\frac{1}{m}$

Hence,

$\begin{gathered} \perp m=-\frac{1}{-\frac{8}{3}} \\ \perp m=\frac{3}{8} \end{gathered}$

Therefore,

$\perp m=\frac{3}{8}$

Next, we are to find the distance KP

Using the formula

$KP=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}$

This gives

$\begin{gathered} KP=\sqrt[]{(-3-(-6))^2+(-2-6)^2} \\ KP=\sqrt[]{3^2+(-8)^2} \\ KP=\sqrt[]{9+64} \\ KP=\sqrt[]{73} \end{gathered}$

Therefore,

$\text{Distance }=\sqrt[]{73}$

Next, equation of the line

The equation can be calculated using

$\frac{y-y_1}{x-x_1}=m$

By inserting values we have

$\begin{gathered} \frac{y-6}{x-(-6)}=-\frac{8}{3} \\ \frac{y-6}{x+6}=-\frac{8}{3} \\ y-6=\frac{-8}{3}(x+6) \\ y-6=-\frac{8}{3}x-6(\frac{8}{3}) \\ y-6=-\frac{8}{3}x-16 \\ y=-\frac{8}{3}x-16+6 \\ y=-\frac{8}{3}x-10 \end{gathered}$

Therefore the equation is

$y=-\frac{8}{3}x-10$

4 0

2 years ago