Answer: provided in the explanation section
Explanation:
Given that:
Assume D(k) =║ true it is [1 : : : k] is valid sequence words or false otherwise
now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.
So, from here we have that D(k) is given by the following recorance relation:
D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise
Algorithm:
Valid sentence (s,k)
D [1 : : : k] ∦ array of boolean variable.
for a ← 1 to m
do ;
d(0) ← false
for b ← 0 to a - j
for b ← 0 to a - j
do;
if D[b] ∧ DICT s([b + 1 : : : a])
d (a) ← True
(b). Algorithm Output
if D[k] = = True
stack = temp stack ∦stack is used to print the strings in order
c = k
while C > 0
stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c
P = W (p) - 1
output stack
= 0 =
cheers i hope this helps !!!
The answer is c because the perpendicular bicector alligns.
Answer:
The statement in python is as follows:
to_the_power_of(cube_side,3)
Explanation:
As stated as the requirement of the code segment, the statement takes as parameters a variable cube_side and a constant 3.
It then returns the volume of the cube; i.e. cube raise to power 3
<em></em>
<em>See full program below</em>
<em>def to_the_power_of(val,powe):</em>
<em> result = val**powe</em>
<em> print(result)</em>
<em>cube_side = float(input("Cube side: "))</em>
<em>to_the_power_of(cube_side,3)</em>
Yes. Feedly will help me create an effective personal online environment. I am able to keep up with all the topics that matter to me most. Feedly is able to help me discover insightful sources from publications and blogs. Feedly is also able to uniquely offer clean, minimalist reading experience optimized for productivity.
Answer:
Internet
Explanation:
The "Cloud" is an Online service this means it works on the Internet and without the Internet you can't have access to it.
