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valkas [14]
3 years ago
6

Скласти рівняння еліпса, фокуси якого розміщені на осі абсцис симетрично початку координат, знаючи, що відстань між фокусами2с=

4 і
ексцентриситет E=2/20
Mathematics
1 answer:
vlada-n [284]3 years ago
3 0

Answer:

Я думаю Е Е/20..........

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Step-by-step explanation:

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This means that

P(5) = 2P(0)

Which lets us find r.

P(t) = P(0)(1+r)^{t}

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