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castortr0y [4]
3 years ago
14

F(x)=-x^2-10x find f(-7)

Mathematics
1 answer:
LenKa [72]3 years ago
4 0

=Answer:

Step-by-step explanation:

f(-7) = -(-7)^2 - 10(-7) = -49 +70 = 21

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Which choice does NOT describe a parallelogram?
weeeeeb [17]

Answer: B. A quadrilateral that has diagonals that do not bisect each other.

Step-by-step explanation:

  • A parallelogram is a quadrilateral whose opposite sides are equal or congruent and parallel. Also, the opposite sides in parallelogram are equal or congruent and the sum of  two adjacent angles is 180 degrees.The diagonals of parallelogram bisect each other.

Therefore by the properties of parallelogram the choice that does NOT describe a parallelogram is " <em>A quadrilateral that has diagonals that do not bisect each other</em>.".

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3 years ago
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School lunches cost ₱35.50 per week. about how much would 15.5 weeks of lunches cost?grade v​
Goryan [66]

Answer:

₱ 550.25

Step-by-step explanation:

₱ 35.50 * 15.5 weeks = ₱ 550.25

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A plan that costs $29.99 another company $19.99 and $0.35 during nights and weekends for what numbers of night and weekend does
Masja [62]

Answer:

<em>29 minutes more</em>

Step-by-step explanation:

Let m represent minutes

changing the statement to algebra, since the second company charges a different rate at night and weekend  we have the equation below;

$19.99 + $0.35m > $29.99

Subtract 19.99 from both sides to isolate m and we have;

$19.99 -$19.99 + $0.35 > $29.99 - $19.99

= $0,35m > $10.00

Divide both side by 0.35 to obtain the value of m;

\frac{0.35m}{0.35} > \frac{10}{0.35}

= m > 28.57

<em>m ⩾ 29 minutes</em>

<em>The second company's will be twenty nine minutes or more costlier than the first company</em>

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3 years ago
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Help please! (no one was answering it in physics and i really need help)
aivan3 [116]

Let v_0 be the cat's speed just as it leaves the edge of the table. Then taking the point 1.3 m below the edge of the table to be the origin, the cat's horizontal position at time t is given by

x(t)=v_0t

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y(t)=1.3\,\mathrm m-gt^2

where g is 9.8 m/s^2, the magnitude of the acceleration due to gravity.

The time it takes for the cat to hit the ground is t with

0=1.3\,\mathrm m-gt^2\implies t=\sqrt{\dfrac{1.3\,\rm m}g}\approx0.36\,\mathrm s

(Unfortunately, this doesn't match any of the given options...)

The cat lands 0.75 m away (horizontally) from the edge of the table, so that its speed v_0 was

0.75\,\mathrm m=v_0(0.36\,\mathrm s)\implies v_0\approx2.08\dfrac{\rm m}{\rm s}

(Again, not one of the answer choices...)

I'm guessing there's either a typo in the question or answers.

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Vanyuwa [196]

Answer:

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I am a master in mathematics!!

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