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4 years ago

What is a nonlinear function

Mathematics

2 answers:

Tema [17]4 years ago

8 0

Answer: A set of dots that arent in a line-esc shape.

(Think of a scatter plot)

I'm bad at explaining, sorry.

Anettt [7]4 years ago

5 0

The best way to define this is *any highest degree term greater than 1⃣*.

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<img src="https://tex.z-dn.net/?f=%20%7B4%7D%5E%7B3%7D%20" id="TexFormula1" title=" {4}^{3} " alt=" {4}^{3} " align="absmiddle"

quester [9]

Answer:

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

What three consecutive integers equal -87?

olchik [2.2K]

Answer:

What three consecutive integers have a sum of 87? Which means that the first number is 28, the second number is 28 + 1 and the third number is 28 + 2. Therefore, three consecutive integers that add up to 87 are 28, 29, and 30. We know our answer is correct because 28 + 29 + 30 equals 87 as displayed above.

Step-by-step explanation:

Consecutive integers are as simple as 1, 2, 3!

Integers are consecutive if one follows another. How do we "jump" from one integer to the next? We add 1, right? 7, 8 and 9 are three consecutive integers. Add one to 7 to get 8 and add one more to get 9.

Now lets think about this in algebraic terms. Lets name these consecutive integers , x, y and z.

The problem tells us that their sum is -87. (Recall, "sum" is just a fancy word for the answer when we add.)

x+y+z = -87

Here is the trick! We need to rewrite this equation so that we have only one variable. Easy!

y is one more that x, so y= x+1

And z is one more than y, so z= y+1. But y is also equal to (x+1)! So z=y+1=(x+1)+1=x+2

Now we have a problem that we can solve! x+(x+1)+(x+2)=-87.

Combining term.: 3x+3=-87

Subtract 3 from both sides of the equation: 3x=84

Divide each side of the equation by 3: x=28

We have solved for x, but we are not done! We need to find y and z. I know you can do this. Remember y is one more than x and z is one more than y.

Check your work! Make sure these three consecutive numbers do in fact add up to -87.

4 0

3 years ago

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

7 0

3 years ago

Simplify, Write your answer in exponential notation.<br> a.) 2³ x 2-5<br> b.) (602)3

mariarad [96]

The simplified expressions are 2^-2 and 60^6

<h3>How to simplify the expressions?</h3>

<u>Expression (a)</u>

We have:

2^3 * 2^-5

Apply the product law of indices

2^3 * 2^-5 = 2^(3 - 5)

Evaluate the difference

2^3 * 2^-5 = 2^-2

<u>Expression (b)</u>

We have:

(60^2)^3

Apply the power law of indices

(60^2)^3 = 60^(2 * 3)

Evaluate the product

(60^2)^3 = 60^6

Hence, the simplified expressions are 2^-2 and 60^6