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Ber [7]
2 years ago
8

Sarah designed 35 video games that designed 3 times as many video games how many more video games did trey design

Mathematics
1 answer:
olga2289 [7]2 years ago
8 0
Trey designed 105 games, so he designed 70 more games. The way the question is worded is weird.
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Please Helpp mee
Mekhanik [1.2K]

Answer:

Step-by-step explanation:

Perpendicular lines are lines whose slopes are negative reciprocals of each other

To find the slope of the line we are given, we can rearrange the equation

4x - 5y = 4\\4x - 4 = 5y\\y = \frac{4}{5}(x) - \frac{4}{5}

The slope of this line is \frac{4}{5}, so the slope of the other line is \frac{-5}{4}

next, we can use the given point to find the equation y = mx +b

we know m, we can solve for b

y = \frac{-5}{4}(x) + b\\-3 = \frac{-5}{4}(-2) + b\\-3 = \frac{5}{2} + b\\\frac{-6}{2} = \frac{5}{2} + b\\

b = \frac{-11}{2}

so,\\y = \frac{-5}{4}(x) - \frac{11}{2}

4 0
3 years ago
For the points in the table, does pressure vary directly with volume? If so, identify k and write an equation. No, this is not a
wel
Can't see the table but direct variation is: y = kx
So if the output is some constant multiple which could be positive, negative or fraction then yes it is direct variation. So just divide a couple y/x = k to see what you get.
7 0
3 years ago
Read 2 more answers
If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?
eduard

Answer:

cos(\alpha+\beta)=-\frac{84}{85}

Step-by-step explanation:

we know that

cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)

Remember the identity

cos^{2} (x)+sin^2(x)=1

step 1

Find the value of sin(\alpha)

we have that

The angle alpha lie on the III Quadrant

so

The values of sine and cosine are negative

cos(\alpha)=-\frac{8}{17}

Find the value of sine

cos^{2} (\alpha)+sin^2(\alpha)=1

substitute

(-\frac{8}{17})^{2}+sin^2(\alpha)=1

sin^2(\alpha)=1-\frac{64}{289}

sin^2(\alpha)=\frac{225}{289}

sin(\alpha)=-\frac{15}{17}

step 2

Find the value of cos(\beta)

we have that

The angle beta lie on the IV Quadrant

so

The value of the cosine is positive and the value of the sine is negative

sin(\beta)=-\frac{4}{5}

Find the value of cosine

cos^{2} (\beta)+sin^2(\beta)=1

substitute

(-\frac{4}{5})^{2}+cos^2(\beta)=1

cos^2(\beta)=1-\frac{16}{25}

cos^2(\beta)=\frac{9}{25}

cos(\beta)=\frac{3}{5}

step 3

Find cos⁡ (α + β)

cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)

we have

cos(\alpha)=-\frac{8}{17}

sin(\alpha)=-\frac{15}{17}

sin(\beta)=-\frac{4}{5}

cos(\beta)=\frac{3}{5}

substitute

cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})

cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}

cos(\alpha+\beta)=-\frac{84}{85}

4 0
3 years ago
What's the unit fraction of 23/138?
Mice21 [21]
1/6 If you have a graphing calculator, it would be simple to type in the fraction as a division equation then type MATH, ENTER, ENTER.
7 0
3 years ago
Read 2 more answers
Above are two different models of the same triangular-shaped garden. If the height of the model on the left is 15 cm, what is th
NNADVOKAT [17]

Answer: The height of the model on the right is 22.5 cm .

Step-by-step explanation:

We can see that , the given different models of the same triangular-shaped garden are similar.

For the first model 1 cm = 3.75 m

whereas for the second model 1 cm = 2.5 m

Now , the constant rate of proportion for this (k) = \dfrac{3.75}{2.5}=\dfrac{375}{250}=1.5

Now , if height of the model on the left is 15 cm , then the height of the model on right = 15 x k

= 15 x 1.5

= 22.5 cm

Hence, the height of the model on the right is 22.5 cm .

8 0
3 years ago
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