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sladkih [1.3K]
1 year ago
8

I can’t figure this out. Help!

Mathematics
2 answers:
Roman55 [17]1 year ago
7 0

Answer:

x is about 6.857 or 48/7

Step-by-step explanation:

to do this we cross multiply

42/18=16/x

42x=18(16)

42x=288

x=6.857

Hopes this helps please mark brainliest

77julia77 [94]1 year ago
3 0

Answer:

Your answer should be x = \frac{48}{7}.

Hope this helps.

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What event would be complementary to the event that the product is an even number?
Phantasy [73]
The only possibility if a number is not even is that it is odd. Thus, the event would be the product is an odd number.
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3 years ago
T(8,2) is reflected across the x-axis.
skad [1K]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ T (8, 2) reflected across the x-axis is (8, -2). When you reflect over the x-axis, the sign in front of the y coordinate changes. When you reflect over the y-axis, the sign in front of the x coordinate changes.

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6 0
3 years ago
Determine the product (4.2×10^-1)+(5.7+10^-1)
Alenkasestr [34]

Answer: (D) 2.394 * 10^-1

Step-by-step explanation:

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= 2.394 * 10^-1

4 0
3 years ago
Please help asap, will mark brainlest. Thanks
mixer [17]

Answer:

2.

4x^2 + 4 - 5x + x - 2x^2 + 8

= (4x^2 - 2x^2) + (x - 5x) + (4 + 8)

= 2x^2 - 4x + 12

=> D is correct

3.

2x^2 + 6x - 7x + 8 - 3x^2 + 1

= (2x^2 - 3x^2) + (6x - 7x) + (1 + 8)

= -x^2 - x + 9

=> C is correct

4.

B is correct (4 and 3)

Hope this helps!

:)

3 0
3 years ago
Daily low temperatures in Columbus, OH in January 2014 were approximately normally distributed with a mean of 15.45 and a standa
Alona [7]

Answer: 12.10

Step-by-step explanation:

Given : Mean : \mu = 15.45

Standard deviation : \sigma = 13.70

The formula to calculate the z-score :-

z=\dfrac{x-\mu}{\sigma}

For x= 5 degrees

z=\dfrac{5-15.45}{13.70}=-0.7627737226\approx-0.76

For x= 10 degrees

z=\dfrac{10-15.45}{13.70}=-0.397810218\approx-0.40

The P-value : P(-0.76

=0.3445783-0.2236273=0.120951\approx0.1210

In percent , 0.1210\times100=12.10\%

Hence, the percentage of days had a low temperature between 5 degrees and 10 degrees = 12.10%

5 0
3 years ago
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