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sladkih [1.3K]
1 year ago
8

I can’t figure this out. Help!

Mathematics
2 answers:
Roman55 [17]1 year ago
7 0

Answer:

x is about 6.857 or 48/7

Step-by-step explanation:

to do this we cross multiply

42/18=16/x

42x=18(16)

42x=288

x=6.857

Hopes this helps please mark brainliest

77julia77 [94]1 year ago
3 0

Answer:

Your answer should be x = \frac{48}{7}.

Hope this helps.

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A triangular lot has sides of 215m, 185m, and 125m. Find the measures of the angles at its corners
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Answer:

The measures of the angles at its corners are 59.1\°,35.4\°,85.5\°

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)

2(215)(125)cos(A)= 215^{2}+125^{2}-185^{2}

cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))cos(A)=0.513953

A=arccos(0.513953)=59.1\°

step 2

Find the measure of angle B

Applying the law of cosines

125^{2}= 215^{2}+185^{2}-2(215)(185)cos(B)

2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}

cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))cos(B)=0.81489

B=arccos(0.81489)=35.4\°

step 3

Find the measure of angle C

Applying the law of cosines

215^{2}= 125^{2}+185^{2}-2(125)(185)cos(C)

2(125)(185)cos(C)= 125^{2}+185^{2}-215^{2}

cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))cos(C)=0.0784

C=arccos(0.0784)=85.5\°

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Step-by-step explanation:

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