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guapka [62]
3 years ago
12

Kayden was offered a job that paid a salary of $39, 500 in its first year. The salary

Mathematics
1 answer:
Allushta [10]3 years ago
6 0

Answer:

FV= $385,307.82

Step-by-step explanation:

Giving the following formula:

Annual salary (A)= $39,500

Growth rate (g)= 2% annual

Number of years (n)= 9 years

<u>To calculate the total amount earned over 9 years, we need to use the following formula:</u>

FV= {A*[(1+g)^n-1]}/g

A= annual deposit

FV= {39,500*[(1.02^9) - 1]} / 0.02

FV= $385,307.82

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If a=-1,b=-6 and c=2 then what is the value of b2-4ac?​
grandymaker [24]

Answer:

-4

Step-by-step explanation:

(-6)(2)-4(-1)(2)

(-12)-(-8)

-12+8=-4

4 0
4 years ago
When the turnpike littered the toll, traffic increased from 1,500 cars per day to 2,700
umka21 [38]

Answer:

  80%

Step-by-step explanation:

The percentage change between two numbers can be calculated as ...

  percentage change = ((new value)/(old value) -1) × 100%

  = (2700/1500 -1) × 100% = (1.80 -1) × 100% = 80%

Traffic volume increased 80%.

6 0
4 years ago
Use the functions f(x) and g(x) to answer the question. F(x)=x²-16; g(x)=x+4
AnnZ [28]

(x^2) - 16 / x+4 = (x-4)(x+4) / (x+4) = x-4, x not equal to -4

D is the answer.

7 0
3 years ago
PLEASE HELP ME!!!!!!! THIS IS TIMED!!!!!!!!! PLEASE HELP ME!!!!!!!!! PLEASE!!!!!!!!!!!!!
Cerrena [4.2K]

Answer:

the probability is 2/24 or 8.3%

Step-by-step explanation:

4 0
3 years ago
If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?​
enyata [817]

Step-by-step explanation:

\bf➤ \underline{Given-} \\

\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\

\bf➤ \underline{To\: find-} \\

\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\

\bf ➤\underline{Solution-} \\

<u>Let us assume that:</u>

\rm: \longmapsto u =  {x}^{2013}

<u>Therefore, the equation becomes:</u>

\rm: \longmapsto u +  \dfrac{1}{u}  = 2

\rm: \longmapsto \dfrac{  {u}^{2} + 1}{u}  = 2

\rm: \longmapsto{u}^{2} + 1 = 2u

\rm: \longmapsto{u}^{2} - 2u + 1 =0

\rm: \longmapsto  {(u - 1)}^{2} =0

\rm: \longmapsto u = 1

<u>Now substitute the value of u. We get:</u>

\rm: \longmapsto {x}^{2013}  = 1

\rm: \longmapsto x = 1

<u>Therefore:</u>

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 1 + 1

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 2

★ <u>Which is our required answer.</u>

\textsf{\large{\underline{More To Know}:}}

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

6 0
3 years ago
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