What is the greatest common factor or 12a and 9a^2

1 answer:

8 0

The factors of 9 are 1, 3 and 9.
The factors of 12 are 1, 2, 3, 4, 6 and 12.
The factor of a and a^2 is just "a."

For coefficients, the common factors of 9 and 12 are 1 and 3 only. But the greatest common factor is 3.
For variables, the greatest factor is just also "a."

Multiplying these two factors, we get the answer: 3a

You might be interested in

You ask 179 of your classmates how they feel about the school year being made longer. Complete the two-way frequency table to s

defon

Answer:

The answer are in the file

5 0

2 years ago

2. A(n) _______________ system is a system of equations with an infinite number of solutions.

Anna11 [10]

Answer:

If a system has infinitely many solutions, then the lines overlap at every point. In other words, they're the same exact line! This means that any point on the line is a solution to the system. Thus, the system of equations above has infinitely many solutions.

Step-by-step explanation:

4 0

3 years ago

Jessica got a prepaid debit card with $20 on it. For her first purchase with the card, she bought some bulk ribbon at a craft st

faltersainse [42]

I don’t know but can you please help me out

5 0

2 years ago

6 painters can paint the fence in 15 hours. How long would it take 5 workers to do the same job?

SOVA2 [1]

Answer:

12.5 hours

Step-by-step explanation:

15/6 is 2.5. 2.5 is how many hours per worker. 5 times 2.5 is 12.5 hours

8 0

3 years ago

Read 2 more answers

If the demand function for a commodity is given by the equation

Jet001 [13]

Answer:

q=26.92 p=31.13

Step-by-step explanation:

$p^{2} +16q=1400\\\\q=\frac{1400-p^{2} }{16} ;\\\\700-p^{2} +10q=0\\\\q=\frac{p^{2}-700 }{10} ;\\\\$

$q=q\\\\\frac{1400-p^{2} }{16} =\frac{p^{2}-700 }{10} \\\\10(1400-p^{2})=16(p^{2}-700)\\\\14000-10p^{2}=16p^{2}-11200\\\\14000+11200=16p^{2}+10p^{2}\\\\25200=26p^{2}\\\\p^{2}=\frac{25200}{26} \\\\p=+\sqrt{\frac{25200}{26}} \\\\p=31.13$

replace p in any equation and

$q=\frac{1400-p^{2} }{16} \\\\q=\frac{1400-(31.13)^{2} }{16}\\\\q=26.92$

3 0

4 years ago