Answer: 586.59 cubic centimeters .
Step-by-step explanation:
As per given . we have
Inner diameter = 1.8 inches
⇒Inner radius :r = 0.9 in. (radius is half of diameter)
= 0.9 x (2.54) = 2.286 cm [∵ 1 in . = 2.54 cm]
Outer diameter = 2 inches
⇒Outer radius : R = 1 inch = 2.54 cm
Height : h = 5 feet = 5 x(30.48) = 152.4 cm [∵ 1 foot = 30.48 cm]
The formula to find the volume of a hollow cylinder :
, where R= outer radius , r= inner radius and h= height.
Now , the volume of metal in the conduit :
![V=(3.14)(( 2.54)^2-(2.286)^2)(152.4)](https://tex.z-dn.net/?f=V%3D%283.14%29%28%28%202.54%29%5E2-%282.286%29%5E2%29%28152.4%29)
![V=(3.14)(6.4516-5.225796)(152.4)](https://tex.z-dn.net/?f=V%3D%283.14%29%286.4516-5.225796%29%28152.4%29)
![V=(3.14)(1.225804)(152.4)](https://tex.z-dn.net/?f=V%3D%283.14%29%281.225804%29%28152.4%29)
![V=586.591342944\approx586.59\ cm^3](https://tex.z-dn.net/?f=V%3D586.591342944%5Capprox586.59%5C%20cm%5E3)
Hence, the volume of metal in the conduit is 586.59 cubic centimeters .