The solution to the problem is as follows:
<span>cos2A - cos4A = -2 sin(6A/2).sin(-2A/2) = +2 sin(3A).sinA
and
sin4A - sin2A = 2 cos(6A/2).sin(2A/2) = 2 cos(3A).sinA
Hence RHS = (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) = sin 3A / cos 3A = tan 3A = LHS
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Answer:
Step-by-step explanation:
The formula for the trigonometric function sin is:
Ф
The side opposite to the ∠g is x, which is equal to 10
the hypotenuse of the triangle is z, which is equal to 11
so the ratio is:
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Answer:
reflection, then rotation, then translation
Step-by-step explanation:
Read the problem statement. It tells you the sequence:
Triangle A B C is <em>reflected</em> across B C to form triangle A prime B C. Triangle A prime B C is <em>then rotated</em> about point A to form A prime B prime C prime. Triangle A prime B prime C prime is <em>then shifted to the right</em> to form A double-prime B double-prime C double-prime.
The transformations are ...
reflection, then rotation, then translation
Answer:
75/100
=15/20
3/4
The probability is3/4
Step-by-step explanation:
75% × x = 56 or, 75/100 × x = 56
Multiplying both sides by 100 and dividing both sides by 75,
we have x = 56 × 75/100
x = 74.667
