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3 years ago

What is the slope of the lone passing through the points (-1,3) and (4,-7)?

Mathematics

2 answers:

trapecia [35]3 years ago

8 0

Answer:

look at the picture shown

laila [671]3 years ago

7 0

Answer:

the answer would be -2

Step-by-step explanation:

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What is the difference between a copay and coinsurance?

bearhunter [10]

Answer:

A deductible is the amount you pay for a service before the plan shares the cost of the service with you. A copay is a set amount you pay for the service. Coinsurance is when you pay a percentage of the cost for an item or service.

4 0

3 years ago

Sinplify this expression -3(10x+4y)+6(6x-2y)

ad-work [718]

Answer:

6x-24y

Step-by-step explanation:

Step 1: -30x-12y+36x-12y

Distribute-3 to 10x and 4y

Then distribute 6 to 6x and -2y

Step 2: 6x-24y

After that add up like terms

3 0

3 years ago

Multiple Representations:Question 1

alexdok [17]

Answer:

y = 27.1

Step-by-step explanation:

We have the value of x:

x = 12

and we need to find the value of y in the expression:

y = x + 15.1

as we can see by the equation, the value of y depends on the value of x.

thus, we substitute x = 12 on the previous equation:

y = 12 + 15.1

y = 27.1

the value of y is 27.1

7 0

2 years ago

What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0?

s344n2d4d5 [400]

Answer:

2 units

Step-by-step explanation:

The given equation of the circle is:

$x^{2} + y^{2}+8x-6y+21=0$

The general equation of the circle is:

$x^{2} + y^{2}+2gx+2fy+c=0$

Comparing the given equation with the general equation we can say:

g = 4

f = -3

c = 21

The formula for radius of the circle is:

$radius=\sqrt{g^{2} +f^{2} -c }$

Using these values of the given circle, we get:

$radius=\sqrt{(4)^{2}+(-3)^{2}-21}\\\\radius=\sqrt{4}\\\\radius=2$

Therefore, the length of radius of the given circle is 2.

3 0

2 years ago

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = ln(x), [1, 5]

matrenka [14]

Answer:

Yes, the function satisfies the hypothesis of the Mean Value Theorem on the interval [1,5]

Step-by-step explanation:

We are given that a function

$f(x)=ln(x)$

Interval [1,5]

The given function is defined on this interval.

Hypothesis of Mean Value Theorem:

(1) Function is continuous on interval [a,b]

(2)Function is defined on interval (a,b)

From the graph we can see that

The function is continuous on [1,5] and differentiable at(1,5).

Hence, the function satisfies the hypothesis of the Mean Value Theorem.

5 0

3 years ago