Question

The length of a rectangle is (x^2- 4x+2) feet and the width is (x+4) feet

Answer 1

Answer:

$A=x^3-14x+8$

Step-by-step explanation:

Given that,

Length of a rectangle, $l=(x^2- 4x+2)$

Width of a rectangle, $b=(x+4)$

We need to find the area of the rectangle.

We know that,

Area of a rectangle = l × b

Substituting all the values,

$A=(x^2- 4x+2)\times (x+4)\\\\=x^3+4x^2-4x^2-16x+2x+8\\\\=x^3-14x+8$

Hence, the area of the rectangle is $x^3-14x+8$.