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Crazy boy [7]
2 years ago
8

What two integers have a sum of -7 and a product of -18?

Mathematics
2 answers:
olga nikolaevna [1]2 years ago
7 0
The other person is right imo! commenting so u give them brainliest <3
Elis [28]2 years ago
5 0

Answer:

-9 and 2

Step-by-step explanation:

-9 x 2

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David wants to buy 16 bolts from a bin at the hardware store. Each bolt cost $0.03. How much will David pay for the bolts
Sav [38]
The answer is .48 cents
5 0
3 years ago
Read 2 more answers
Need help please somebodt
Nostrana [21]
A≈21.46
First you find the area of the square

A=a^2 which is
=10^2
A=100

Then you find the area of the circle
A=πr^2
= π(5)^2
A≈78.54

Now you subtract the 78.54 from 100 to get 21.46
5 0
3 years ago
I need the answer asap
mina [271]

Answer:

(a) 1.353 x 10^9

Step-by-step explanation:

Jumping 9 places back to obtain standard form

7 0
2 years ago
Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into
Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = (\frac{60\pi }{\pi+4}) in

b)the length of the wire for the square = (\frac{240}{\pi+4}) in

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

         b=\frac{y}{4}

Area of the square which is L² can now be said to be;

A_S=(\frac{y}{4})^2 = \frac{y^2}{16}

On the otherhand; let the radius (r) of the  circle be;

2πr = 60-y

r = \frac{60-y}{2\pi }

Area of the circle which is πr² can now be;

A_C= \pi (\frac{60-y}{2\pi } )^2

     =( \frac{60-y}{4\pi } )^2

Total Area (A);

A = A_S+A_C

   = \frac{y^2}{16} +(\frac{60-y}{4\pi } )^2

For the smallest possible area; \frac{dA}{dy}=0

∴ \frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0

If we divide through with (2) and each entity move to the opposite side; we have:

\frac{y}{18}=\frac{(60-y)}{2\pi}

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

y= \frac{240}{\pi+4}

∴ since y= \frac{240}{\pi+4}, we can determine for the length of the circle ;

60-y can now be;

= 60-\frac{240}{\pi+4}

= \frac{(\pi+4)*60-240}{\pi+40}

= \frac{60\pi+240-240}{\pi+4}

= (\frac{60\pi}{\pi+4})in

also, the length of wire for the square  (y) ; y= (\frac{240}{\pi+4})in

The smallest possible area (A) = \frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0
3 years ago
Factor the expression 48x+8 using the GCF
ololo11 [35]
<span> 48x+8 = 8(6x+1) </span>← Answer
3 0
3 years ago
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