D) Alt Tags thats the answer i think
Answer:
The server-based network has some disadvantages such as hardware-accelerated which is affordable. Effective operating system with a network. Requires a dedicated system administrator.
Explanation:
- When one of the databases drops south all the people are being affected and the whole network can even be downgraded.
- Costlier to set up and maintain.
- Expensive:
- The expensive server hardware equipment, database software platforms, and network installation can require significant source host and system administrator.
- Administrating:- Appears to require continual servicing by the system administrator and admin must behave with the relevant skills to preserve also that network infrastructure tracking is an important requirement.
- Server Failure:
- The complete functionality of the system is hosting events. If the server crashes, the whole system will go away even though all the customers rely solely on the computer.
- Heavy Traffic:- The server is the infrastructure for managing entire elements of the organization that offer the server overload. Internet traffic will be even more relevant as the customer must start their contact session from boot time to disconnect. System routing must be properly maintained otherwise it tends to lead this same computer as a crowded state or the standard processes will be affected.
Answer: Persistent
Explanation:
Persistent is the type of connection in the hyper text transfer protocol (HTTP) that act as communication channel in the network. It basically remain open after HTTP request or response to the server.
Persistent also maintain the HTTP connection and prevent it from the timing out with the help of transmission control protocol packets.
In the persistent connection, after request has been send TCP connection is leave by the server. Therefore, the request can be easily send between the similar server and client.
Answer:
- import java.util.Scanner;
-
- public class Main {
- public static void main(String[] args) {
- Scanner input = new Scanner(System.in);
- String numStr = input.nextLine();
- double num;
- try{
- num = Double.parseDouble(numStr);
- }
- catch(NumberFormatException e){
- num = 0;
- System.out.println("Value entered cannot be converted to a floating point number.");
- }
- }
- }
Explanation:
The solution code is written in Java.
Firstly, we create a Scanner object and prompt user to input a number (Line 5-6). Next, we create a try -catch block and place the parseDouble inside the try block. If the input is invalid (e.g. "abc"), a NumberFormatException error will be thrown and captured and set the num to 0 and display the error message (Line 11 - 13).
