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otez555 [7]
2 years ago
12

Will mark Brainliest, need help ASAP!

Computers and Technology
1 answer:
Whitepunk [10]2 years ago
3 0

Answer:

What Sherman needs to configure is:

RIPv2 class D of 240.

Explanation:

Multicast messages are usually dispatched to a select group of hosts on a network and require acknowledgement of the recipients. RIPv2 is a router-based internet protocol for exchanging routing information to the IP address 224.0. 0.9 on a network. It determine the most efficient way to route data on a network and to prevent routing loops.

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One drive is microsofts storage service for holding files in the “cloud”. It offers users a simple way to store and sync various types of files with other people/devices on the internet.
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What’s good and bad about having social media?
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Read 2 more answers
Consider a company that needs to sort an array of structures of type Customer by balance, with the largest balance first. Here i
8090 [49]

Answer:

#include <iostream>

#include <string>

#include <cstring>

#include <cstdlib>

using namespace std;

struct Person

{

string name;

int age;

};

int main()

{

struct Person data[10];

struct Person *pData[10],*temp;

string names[] = {"a","b","c","g","z","l","p","q","r","w"};

int num[] = {4,6,34,8,13,90,33,22,18,23};

for(int i=0;i<9;i++)

{

data[i].name = names[i];

data[i].age = num[i];

pData[i] = &data[i];

}

for(int i=0;i<9;i++)

{

for(int j=i+1;j<9;j++)

{

if(pData[i]->name.compare(pData[j]->name)>0)

{

temp = pData[i];

pData[i] = pData[j];

pData[j] = temp;

}

}

}

for(int i=0;i<9;i++)

{

cout<<pData[i]->name<<" "<<pData[i]->age<<endl;

}

}

Explanation:

The line #include <iostream> initializes the program.

This program created an array of only 10 structures, Customer data. Also defined an auxiliary array Customer *pData.

The program uses these parameters to sorts the array of pointers so that when you go through pData in increasing order of index k, the entries pData[k] point to Customer objects in decreasing order by balance, meaning that pdata[0] now points to the customer with the highest balance, and pData[9] points to the customer with the smallest balance.

4 0
3 years ago
Which action does not happen in each iteration of the repeat loop in the
iren2701 [21]

B. The number of sharks decreases. Explanation: hope it's help i learned about it and you too

7 0
2 years ago
In a C++ program, one and two are double variables and input values are 10.5 and 30.6. After the statement cin &gt;&gt; one &gt;
SSSSS [86.1K]

Answer:

variable one stores 10.5 and two stores 30.6

Explanation:

In c++ language, the cout keyword is used to write to the standard output. The input from the user is taken by using the cin keyword.

For the input from the user, a variable need is declared first.

datatype variable_name;

The input can be taken one at a time as shown.

cin >> variable_name;

The input for more than one variable can be taken in a single line as given by the syntax below.

1. First, two variables are declared.

datatype variable_name1, variable_name2;

2. Both input is taken simultaneously as shown.

cin >> variable_name1, variable_name2;

For the given scenario, two double variables are declared as below.

double one, two;

The question mentions input values for the two double variables as 10.5 and 30.6.

3. The given scenario takes both the values as input at the same time, in a single line as shown below.

cin >> one >> two;

4. After this statement, both the values entered by the user are accepted.

The values should be separated by space.

First value is stored in the variable one.

Second value is stored in the variable two.

5. The user enters the values as follows.

10.5 30.6

6. The value 10.5 is stored in variable one.

7. The value 30.6 is stored in variable two.

The c++ program to implement the above is given below.

#include <iostream>

using namespace std;

int main() {

   double one, two;      

   cout << " Enter two decimal values " << endl;

   cin >> one >> two;

   cout << " The input values are " << endl;

   cout << " one : " << one << " \t " << " two : " << two << endl;

   return 0;

}

OUTPUT

Enter two decimal values  

10.5 30.6

The input values are  

one : 10    two : 530.6

6 0
3 years ago
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