Answer:
x = 3
Step-by-step explanation:
Given :
AE = 3, EB = 4, CE = x, and ED = x +1,
Equating chord AB and CD
AE*EB = CE*ED
3*4 = x*(x+1)
12 = x² + x
x² + x - 12 = 0
x² +4x - 3x - 12 = 0
x(x + 4) - 3(x + 4)
(x + 4) = 0 or (x - 3) = 0
x = - 4 or x = 3
Distance can't be negative :
x = 3
Y+3x=2----equation1
y-2x=-3-----equation 2
e1-e2
(y+3x)-(y-2x)=2-(-3)
y+3x-y+2x=5
5x=5
x=1
sub x=1 into equation 1
y+3(1)=2
y=-1
Full time employees in US = 1740
Total full time employees of Anchor Global Insurance =
1740 + 670 + 300 + 250 + 380 + 135 = 3475
<span>Percentage of full time US employees of Anchor Global
Insurance = (US full time employees / total full time employees) x 100 = (1740 /
3475) x 100 = 50.0719 %</span>
5 animals are going towards the river .
<u>Step-by-step explanation:</u>
Here we have , One rabbit saw six elephants while going to the river. Every elephant saw 2 monkeys going towards the river. Every monkey holds one parrot in their hand.We need to find How many animals are going towards the river . Let's find out:
- 1 rabbit saw 6 elephants while going to the river. i.e. rabbit is only going towards river !
- Every elephant saw 2 monkeys going towards the river. From the sentence , each of the 6 elephants saw 2 monkeys going towards the river, hence will be 6 x 2 = 12 monkeys going towards the river.
But, the statement does not explicitly say that “Every elephant saw 2 DIFFERENT monkeys…”, therefore implicit rules apply and infer that the 2 monkeys are the same. So , every elephant saw 2 monkeys!
- Now , every monkey holds 1 parrot in their hands. 2 parrots are going towards the river.
So , total number of animals is :
⇒ 
⇒ 
Therefore , 5 animals are going towards the river .
Solve for x:x/5 - 2 = x/2 + 3
Put each term in x/5 - 2 over the common denominator 5: x/5 - 2 = x/5 - (10)/5:x/5 - (10)/5 = x/2 + 3
x/5 - (10)/5 = (x - 10)/5:(x - 10)/5 = x/2 + 3
Put each term in x/2 + 3 over the common denominator 2: x/2 + 3 = x/2 + 6/2:(x - 10)/5 = x/2 + 6/2
x/2 + 6/2 = (x + 6)/2:(x - 10)/5 = (x + 6)/2
Multiply both sides by 10:(10 (x - 10))/5 = (10 (x + 6))/2
10/5 = (5×2)/5 = 2:2 (x - 10) = (10 (x + 6))/2
10/2 = (2×5)/2 = 5:2 (x - 10) = 5 (x + 6)
Expand out terms of the left hand side:2 x - 20 = 5 (x + 6)
Expand out terms of the right hand side:2 x - 20 = 5 x + 30
Subtract 5 x from both sides:(2 x - 5 x) - 20 = (5 x - 5 x) + 30
2 x - 5 x = -3 x:-3 x - 20 = (5 x - 5 x) + 30
5 x - 5 x = 0:-3 x - 20 = 30
Add 20 to both sides:(20 - 20) - 3 x = 20 + 30
20 - 20 = 0:-3 x = 30 + 20
30 + 20 = 50:-3 x = 50
Divide both sides of -3 x = 50 by -3:(-3 x)/(-3) = 50/(-3)
(-3)/(-3) = 1:x = 50/(-3)
Multiply numerator and denominator of 50/(-3) by -1:Answer: x = (-50)/3
