Let's solve your equation step-by-step.
−3x2−4x−4=0
Step 1: Use quadratic formula with a=-3, b=-4, c=-4.
x=
−b±√b2−4ac
2a
x=
−(−4)±√(−4)2−4(−3)(−4)
2(−3)
x=
4±√−32
−6
Answer:
No real solutions.
To add these amounts together, we must first find their least common multiple in order to get common denominators (b/c when you add fractions, the denominators must be the same).
We'll start by listing some of their multiples.
To do this, count by whatever the denominator is:
4 1/2 (denominator is 2): 2 4 6 8 10 12 14
2 1/4 (denominator is 4): 4 8 12 16
6 1/3 (denominator is 3): 3 6 9 12 15
Look and see which is the first multiple that all three denominators have. Circle them if it helps you. In this case, it's 12.
So now we have to multiply the denominators by whatever number it takes to reach 12, and multiply by the same number to the numerator:
4 1/2 (times 6 to both top and bottom) =
4 6/12
2 1/4 (times 3) = 2 3/12
6 1/3 (times 4) = 6 4/12
Add all these fractions together, and you get 12 13/12, which is equal to 13 1/12.
Thus, Peter makes a total of 13 1/2 cups.
Hope this made sense! tell me if anything is confusing/incorrect :))
Answer:
a. 5% of the employees will experience lost-time accidents in both years
b. 24% of the employees will suffer at least one lost-time accident over the two-year period
Step-by-step explanation:
a. What percentage of the employees will experience lost-time accidents in both years?
20% last year, of those who suffered last year, 25% during this year. So
5% of the employees will experience lost-time accidents in both years.
b. What percentage of the employees will suffer at least one lost-time accident over the two-year period?
5% during the two years.
10% during the current year. 25% of employees who had lost-time accidents last year will experience a lost-time accident during the current year.
So the 10% is composed of 5% during both years(25% of 20%) and 5% of the 80% who did not suffer during the first year.
First year yes, not on the second.
75% of 20%. So, total:
24% of the employees will suffer at least one lost-time accident over the two-year period
Answer:option D is correct Log(1/3)
Step-by-step explanation:
Log2-Log6
Log(2/6)
Log(1/3)
