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3 years ago

What is the answer to 1200 x 4500 = ?

Mathematics

2 answers:

aleksandrvk [35]3 years ago

5 0

Answer : 5,400,000

Explanation :

Vitek1552 [10]3 years ago

5 0

Answer:

5400000

Step-by-step explanation:

To make it easier.

12 x 45, then add your four zeros on your answer!

Hope this helps!

Yours Truely, TheAnimeCatUwU

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Jane spent 2/5 of her money on games. She had $120 remaining. What was the cost of the games Jane bought?

Ostrovityanka [42]

Answer:

i think it would be $80 (brainliest??)

Step-by-step explanation:

jane had a total of $200 BEFORE she spent on 2 games

1. $40

2. $40

3. $40

4. $40

5.$40

2 games = $80

3 games = $120 (money she had left)

5 0

3 years ago

Write an equation of a line that passes through (-1,6) and has a slope of 4.

jeka94

Answer:

y-6=4(x+1) or y=4x+10

Step-by-step explanation:

Point: (-1,6)

m=4

Slope-point form is y-y1=m(x-x1)

y1=6

x1=-1

Now, plug it in!

y-6=4(x-(-1)) which is y-6=4(x+1)

Of course, if you want you could always simplify it down to y=4x+10 if you wanted to

Hope this helps!

7 0

3 years ago

Jacob wants to make a graph to show the relationship between temperatures in Fahrenheit and degrees Celsius. He plots the follow

Elena L [17]

"It will not be spread out horizontally across the entire coordinate plane because in Step 4 Jacob selected an incorrect scale on the x-axis" is the one among the following that best describes the graph. You can clearly understand that, once you plot the graph. The correct option among all the options given in the question is the first option. I hope it helps you.

8 0

4 years ago

The age of the children in kindergarten on the first day of school is uniformly distributed between 4.8 and 5.8 years old. A fir

Kazeer [188]

Answer:

(1) (c) 5.30 years.

(2) (b) 0.289.

(3) (b) 0.80.

(4) (d) 0.50.

(5) (a) 5.25 years.

Step-by-step explanation:

Let X = age of the children in kindergarten on the first day of school.

The random variable X follows a continuous Uniform distribution with parameters a = 4.8 years and b = 5.8 years.

The probability density function function of X is:

$f_{X}(x)=\left \{ {{\frac{1}{b-a}} ;\ a$

(1)

The expected value of a Uniform random variable is:

$E(X)=\frac{1}{2}(a+b)$

Compute the mean of X as follows:

$E(X)=\frac{1}{2}(a+b)=\frac{1}{2}\times (4.8+5.8)=5.3$

Thus, the mean of the distribution is (c) 5.30 years.

(2)

The standard deviation of a Uniform random variable is:

$SD(X)=\sqrt{\frac{1}{12}(b-a)^{2}}$

Compute the standard deviation of X as follows:

$SD(X)=\sqrt{\frac{1}{12}(b-a)^{2}}=\sqrt{\frac{1}{12}\times (5.8-4.8)^{2}}=0.289$

Thus, the standard deviation of the distribution is (b) 0.289.

(3)

Compute the probability that a randomly selected child is older than 5 years old as follows:

$P(X>5)=\int\limits^{5.8}_{5} {\frac{1}{5.8-4.8}}\, dx\\$

$=\int\limits^{5.8}_{5} {1}\, dx\\=[x]^{5.8}_{5}\\=(5.8-5)\\=0.8$

Thus, the probability that a randomly selected child is older than 5 years old is (b) 0.80.

(4)

Compute the probability that a randomly selected child is between 5.2 years and 5.7 years old as follows:

$P(5.2$

$=\int\limits^{5.7}_{5.2} {1}\, dx\\=[x]^{5.7}_{5.2}\\=(5.7-5.2)\\=0.5$

Thus, the probability that a randomly selected child is between 5.2 years and 5.7 years old is (d) 0.50.

(5)

It is provided that a randomly selected child is at the 45th percentile.

This implies that:

P (X < x) = 0.45

Compute the value of x as follows:

$P (X < x) = 0.45$

$\int\limits^{x}_{4.8} {\frac{1}{5.8-4.8}}\, dx=0.45$

$\int\limits^{x}_{4.8} {1}\, dx=0.45$

$[x]^{x}_{4.8}=0.45$

$x-4.8=0.45\\$

$x=0.45+4.8\\x=5.25$

Thus, the age of the child at the 45th percentile is (a) 5.25 years.

6 0

3 years ago

2x + бу = -12 5х – бу = 10

OlgaM077 [116]

Let 6x-3y=3 be equation 1 and -2x +6y=14 be equation 2.

Take 2 common from eq 2 let the optioned eq be equation number 3.

And solve eq number 1 and 3.

3 0

3 years ago

Read 2 more answers