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vodka [1.7K]
3 years ago
6

Jacob wants to make a graph to show the relationship between temperatures in Fahrenheit and degrees Celsius. He plots the follow

ing points:. (11, -11.7), (15, -9.4), (25, -3.9), (35, 1.7), (45, 7.2). He uses the following steps to plot the graph:. Label origin as (0, 0). On x-axis label Temperature in Fahrenheit. On y-axis label Temperature in degrees Celsius. The scale on x-axis starts from 0 and goes up to 700 at intervals of 20. The scale on the y-axis starts from -12 and goes up to 12 at intervals of 2. Which of the following best describes the graph?
It will not be spread out horizontally across the entire coordinate plane because in Step 4 Jacob selected an incorrect scale on the x-axis.

It will not be spread out vertically across the entire coordinate plane because in Step 5 Jacob selected an incorrect scale on the y-axis.

It will not be spread out horizontally across the entire coordinate plane because in Step 2 Jacob plotted Fahrenheit instead of Celsius on the axis.

It will not be spread out vertically across the entire coordinate plane because in Step 3 Jacob plotted Celsius instead of Fahrenheit on the y-axis.
Mathematics
1 answer:
Elena L [17]3 years ago
8 0
<span>"It will not be spread out horizontally across the entire coordinate plane because in Step 4 Jacob selected an incorrect scale on the x-axis" is the one among the following that best describes the graph. You can clearly understand that, once you plot the graph. The correct option among all the options given in the question is the first option. I hope it helps you.</span>
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Lynna [10]
7. YZ
8. 27,49
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3 years ago
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Please help me for the brainliest answer
TiliK225 [7]

Answer:

n^2+3\\(n+1)^2

Step-by-step explanation:

n^2+3\\1^2+3=4\\2^2+3=7\\3^2+3=12

(n+1)^2\\(1+1)^2=4\\(2+1)^2=9\\(3+1)^2=16

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3 years ago
Solve for x<br> 35+.8x=43-7x
Vinvika [58]

Answer:

x = 1.02564

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

35 + 0.8x = 43 - 7x

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Addition Property of Equality] Add 7x on both sides:                                 35 + 7.8x = 43
  2. [Subtraction Property of Equality] Subtract 35 on both sides:                    7.8x = 8
  3. [Division Property of Equality] Divide 7.8 on both sides:                             x = 1.02564
7 0
3 years ago
A bridge hand is made up of 13 cards from a deck of 52. find the probability that a hand chosen at random contains at least 3 ki
Vlad [161]
1.
In total there are C(52, 13) ways that we can pick a hand, that is \frac{52!}{13!39!}


2.
P(a hand contains at least 3 kings)
                =P(a hand contains exactly 3 kings)+P(a hand contains 4 kings)

3.
first let's find P(a hand contains exactly 3 kings):

P(a hand contains exactly 3 kings)
              =n(a hand contains exactly 3 kings)/C(52, 13)
              
n(a hand contains exactly 3 kings)=C(4, 3)*C(48, 10)

where C(4,3) is the total number of ways we can pick 3 out of 4 kings,

C(48, 10) is the number of picking 10 letters to complete a hand, out of the 52-4=48 non-king cards.

so P(a hand contains exactly 3 kings)=[C(4, 3)*C(48, 10)]/C(52, 13)

4. with the same reasoning as in step 3:

P(a hand contains 4 kings)=n(a hand contains 4 kings)/C(52, 13)

                          = [C(4, 4)*C(48, 9]/C(52, 13)


5. 

P(a hand contains at least 3 kings)
                =P(a hand contains exactly 3 kings)+P(a hand contains 4 kings)

=[C(4, 3)*C(48, 10)]/C(52, 13)+ [C(4, 4)*C(48, 9)]/C(52, 13)

=\frac{C(4, 3)*C(48, 10)+C(4, 4)*C(48, 9)}{C(52, 13)}

=\frac{4* \frac{48!}{10!38!} + \frac{48!}{9!39!}}{ \frac{52!}{13!39!} }

simplify by 38! in the denominators and 48! in the numerators :

\frac{4* \frac{1}{10!} + \frac{1}{9!39}}{ \frac{52*51*50*49}{13!39} } &#10;&#10;

now simplify by 9! in all denominators:

\frac{ \frac{4}{10}+  \frac{1}{39} }{ \frac{52*51*50*49}{13*12*11*10*39}}


\frac{ 0.426 }{ 9.7} =0.044

4 0
3 years ago
Best tips for revision?
Sergio [31]
I'm n not what you mean but as best as I can tell you looking for tips on writing an essay which is English not math, but I would suggest studying in a quiet place away from distractions such as tv`s and computers and such, also try to keep track of your notes.
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