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Nostrana [21]
3 years ago
14

A repeating decimal + A fraction

Mathematics
2 answers:
AysviL [449]3 years ago
7 0

Answer:

3.33333333333+1/3=3.6666666666666666

Damm [24]3 years ago
3 0

Answer:

yup you're correct, nice job

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I need help to calculate (The three at the end is to the third power!)<br> (−1)3<br> Thank you!!!!!!
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( -1) 3^3

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- 27 is the answer
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What is the answer X/7-3&gt;8
mamaluj [8]

Answer:

x > 77

Step-by-step explanation:

According to order of operations rules, we must carry out division before addition or subtraction.  In this case we wish to isolate x and are permitted to simplify the inequality by combining the "like terms" 3 and 8, as follows:

X/7-3>8

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--------------

x/7 > 11

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3 years ago
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Anestetic [448]

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17 67899887753 o

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100 POINTS+BRAINLIEST 8TH GRADE MATH PT 4: this one is similar to #3
djverab [1.8K]

Answer:

b.  x + (x + 2) + (x + 4) = 39

Step-by-step explanation:

<u>Definitions</u>

  • Integer:  a whole number that can be positive, negative or zero.
    e.g. ..., -3, -2, -1, 0, 1, 2, 3, ...
  • Odd number: an integer that when divided by two leaves a remainder (so not a multiple of 2).  For example, 1, 3, 5, 7 are all positive odd numbers.
  • Consecutive: following one after the other in order.

<u>The sum of three consecutive odd integers</u>

Let x be the first odd integer.

As there is a <u>difference of 2</u> between <u>consecutive odd integers</u>, the next odd integer after x will be (x + 2).

Therefore, the next odd integer after (x + 2) will be (x + 2) + 2 = (x + 4).

So "the sum of three consecutive odd integers is thirty-nine" is:

x + (x + 2) + (x + 4) = 39

<u>To solve</u>

⇒ x + (x + 2) + (x + 4) = 39

⇒ x + x + 2 + x + 4 = 39

⇒ 3x + 6 = 39

⇒ 3x = 33

⇒ x = 11

Therefore, the three consecutive odd numbers are 11, 13 and 15.

6 0
2 years ago
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