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allsm [11]
2 years ago
11

Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
USPshnik [31]2 years ago
7 0

Answer:

The given information tells us that AFD is either an equilateral or isosceles triangle.  We can see by the diagram that it is not equilateral, so the correct answer here would be the second one, "Isosceles".

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Im answering questions on here instead of doing my own school work lol
zhenek [66]

Answer:

omg sameeee

Step-by-step explanation:

lol

3 0
3 years ago
Thomas has 4 blocks colored blue, red ,green and yellow. How many different ways can he combine them on a shelf?
Kipish [7]
64 different possibilities are there
4 0
3 years ago
Given that lines m and n are parallel and that line t is a transversal, the
Naily [24]

Answer:

60

Step-by-step explanation:

if the opposite of <1 is 120 and the line it is sitting on is flat, we can figure out that both connected would be 180

the equation would be 180-120=60

hope this helped

3 0
2 years ago
Read 2 more answers
Help pls help plsssssss
densk [106]

Answer:

bro its 10

Step-by-step explanation:

5 kilometers in 30mins and if he stayed at the same rate for an hour he would have ran 10 kilometers cause 5 x 2 = 10

8 0
3 years ago
It has a time to failure distribution which is normal with a mean of 35,000 vehicle miles and a standard deviation of 7,000 vehi
Triss [41]

Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that \mu = 35000, \sigma = 7000

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

Z = \frac{X - \mu}{\sigma}

-1.88 = \frac{X - 35000}{7000}

X - 35000 = -1.88*7000

X = 21840

The designed life should be of 21,840 vehicle miles.

3 0
2 years ago
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