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snow_tiger [21]
3 years ago
15

Help I’ll mark brainliest

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

ACD

Step-by-step explanation:

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Given: ​△ACE, BD​∥AE<br><br> Prove: BA/CB=DE/CD<br><br> Drag
gizmo_the_mogwai [7]

Answer:


Step-by-step explanation:

Angle 4 = angle 1 and angle 3 =angle 2        Corresponding angles for two        parallel lines BD and AE

Triangle AED ||| BDE                                       Angle angle congruent

...                                                                       By compendo and dividendo

Thus proved

Since two lines are parallel we have corresponding angles equal and also

sides will be proportional in similar triangles

Using that and adjusting compendo and dividendo we get the desired result

6 0
3 years ago
Read 2 more answers
Tom wants to reach a second floor window on a house that is 20 feet above ground. If he must put the ladder at a 70° angle to th
vovangra [49]
Let the ladder length be L, then

sin 70 = 20/L, L = 20/sin70 = 21.3 feet
the length of ladder is 21.3 feet
5 0
2 years ago
What is the value of x?<br> HELP! Please
Anastaziya [24]
D. 68
I don’t remember what formula this is called but the formula says that all angles in a triangle should add up to 180, so 75+37= 112, 180-112= 68
8 0
2 years ago
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Declan draws triangle WXY. He then constructs a perpendicular bisector from vertex W that intersects side XY at point Z. What ca
Ganezh [65]

Answer:

YZ = XZ

Step-by-step explanation:

Perpendicular Bisector:

A perpendicular bisector of a line segment 'l' is a line that is perpendicular to the line segment 'l' and cuts the line segment 'l' into two equal parts.

Given:

1. A triangle WXY.

2. A perpendicular bisector from vertex W that intersects XY at point Z.

Conclusion based on the drawing:

a. Z is the midpoint of the line segment XY because point Z lies on the perpendicular bisector of XY.

b. Hence, XZ = YZ.

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3 years ago
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WHATS THE MEASURE OF ANGLE D
valentina_108 [34]

Answer:

7.6

Step-by-step explanation:

m<DBA is 68 degrees

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